C Program to Check Disarium Number

Posted in C Tutorial

Updated on Jan 11, 2024

By Mari Selvan

👁️ 37 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

🙋 Introduction

In the realm of programming, exploring mathematical patterns is a fascinating endeavor. One such numeric pattern is the Disarium number.

A Disarium number is a number defined by the sum of its digits each raised to the power of its respective position.

In this tutorial, we'll delve into a C program designed to check whether a given number is a Disarium number.

📄 Example

Let's explore the C code that checks whether a given number is a Disarium number.

isDisarium.c

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#include <stdio.h>
#include <math.h>

// Function to count the number of digits in a given number
int countDigits(int number) {
  int count = 0;
  while (number != 0) {
    count++;
    number /= 10;
  }
  return count;
}

// Function to check if a number is a Disarium number
int isDisarium(int number) {
  int originalNumber = number;
  int digitCount = countDigits(number);
  int sum = 0;

  while (number != 0) {
    int digit = number % 10;
    sum += pow(digit, digitCount);
    digitCount--;
    number /= 10;
  }

  return (sum == originalNumber);
}

// Driver program
int main() {
  // Replace this value with your desired number
  int inputNumber = 89;

  // Call the function to check if the number is Disarium
  if (isDisarium(inputNumber)) {
    printf("%d is a Disarium number.\n", inputNumber);
  } else {
    printf("%d is not a Disarium number.\n", inputNumber);
  }

  return 0;
}

💻 Testing the Program

To test the program with different numbers, replace the value of inputNumber in the main function.

Output

89 is a Disarium number.

Compile and run the program to check if the number is a Disarium number.

🧠 How the Program Works

The program defines a function countDigits to count the number of digits in a given number.
The isDisarium function checks if a number is a Disarium number by summing the digits each raised to the power of its position.
The main function tests the isDisarium function with a sample number (replace it with your desired number).

📏 Between the Given Range

Let's dive into the C code that checks for Disarium numbers in the specified range.

isDisarium.c

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#include <stdio.h>
#include <math.h>

// Function to calculate the number of digits in a number
int countDigits(int num) {
  int count = 0;
  while (num != 0) {
    num /= 10;
    ++count;
  }
  return count;
}

// Function to check if a number is a Disarium number
int isDisarium(int num) {
  int originalNum = num;
  int digitCount = countDigits(num);
  int sum = 0;

  while (num != 0) {
    int digit = num % 10;
    sum += pow(digit, digitCount);
    num /= 10;
    --digitCount;
  }

  return (sum == originalNum);
}

// Driver program
int main() {
  printf("Disarium numbers in the range 1 to 100:\n");

  for (int i = 1; i <= 100; ++i) {
    if (isDisarium(i)) {
      printf("%d ", i);
    }
  }

  return 0;
}

💻 Testing the Program

Output

Disarium numbers in the range 1 to 100:
1 2 3 4 5 6 7 8 9 89

Run the program to check for Disarium numbers in the range from 1 to 100.

🧠 How the Program Works

The program defines a function countDigits that calculates the number of digits in a given number.
It also defines a function isDisarium that checks if a number is a Disarium number.
The main function iterates through numbers from 1 to 100 and prints the Disarium numbers in the specified format.