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C# Number Pattern 45

Posted in C# Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 182 - Views
⏳ 4 mins
💬 1 Comment
C# Number Pattern 45

Photo Credit to CodeToFun

C# Number Pattern 45

Here`s a program that prints the above number pattern using C# Programming:

example.cs
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using System;

namespace myApp {
  class Program {
    static void Main(string[] args) {
      int i, j;
      for (i = 1; i <= 4; i++) {
        for (j = 1; j <= 9; j++) {
          if (i == j || j == 5 || i == 10 - j)
            Console.Write("*");
          else
            Console.Write("0");
        }
        Console.WriteLine();
      }
    }
  }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
*000*000*
0*00*00*0
00*0*0*00
000***000

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program begins with a using statement, which is used to import the System namespace. This namespace contains the fundamental classes and base types that are used in C# programs.
  2. Next, the program defines a namespace called myApp. A namespace is used to organize code and avoid naming conflicts.
  3. Inside the myApp namespace, there is a class named Program, which contains the Main method. The Main method is the entry point of the C# program, where the execution starts.
  4. The Main method begins by declaring two integer variables i and j, which will be used in the subsequent for loops.
  5. The first for loop runs from i=1 to i<=4, meaning it will iterate four times. This loop is responsible for printing four rows of characters.
  6. Inside the first for loop, there is another for loop that runs from j=1 to j<=9, meaning it will iterate nine times. This loop is responsible for printing characters within each row.
  7. Inside the nested for loops, there is an if statement to determine which character to print based on the current values of i and j.
  8. The if statement has three conditions:
    1. i == j: If the current value of i is equal to the current value of j, a '*' character is printed. This condition creates the diagonal line of asterisks from the top-left to the bottom-right.
    2. j == 5: If the current value of j is 5, a '*' character is printed. This condition creates the vertical line of asterisks in the middle of the row.
    3. i == 10 - j: If the current value of i is equal to 10 - j, a '*' character is printed. This condition creates the diagonal line of asterisks from the top-right to the bottom-left.
  9. If none of the conditions in the if statement are true, the program prints a '0' character. This is done to fill the rest of the spaces in the row with zeroes.
  10. After printing the characters for each row, the program moves to a new line using Console.WriteLine(), so the next row will be printed on a new line.
  11. Once all iterations are completed for both i and j loops, the program execution ends.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (C# Number Pattern 45) please comment here. I will help you immediately.

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