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Python Alphabet Pattern 31

Posted in Python Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 134 - Views
⏳ 4 mins
💬 1 Comment
Python Alphabet Pattern 31

Photo Credit to CodeToFun

Python Alphabet Pattern 31

Here`s a program that prints the above alphabet pattern using Python Programming:

example.py
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for i in range(65, 70):
    for j in range(65, 70):
        if(i == j):
            a = chr(i)
            print(a, end="")
        else:
            print(" ", end="")
               
    for k in range(68, 64, -1):
        if(i == k):
            a = chr(i)
            print(a, end="")
        else:
            print(" ", end="")
    print()

💻 Testing the Program

When you run the above program, it will print the following output:

Output
A       A
 B     B
  C   C
   D D
    E

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The outer loop for i in range(65, 70): iterates through the ASCII values of characters from 'A' (65) to 'E' (69).
  2. Inside the outer loop, there is another nested loop for j in range(65, 70): which iterates through the same range of ASCII values from 'A' to 'E'. This loop is responsible for printing characters in the first part of each row.
  3. Inside the second loop, there's an if condition: if(i == j):. This checks if the ASCII values of the outer and inner loop variables are the same. If they are equal, it means the program is on the main diagonal of the pattern.
  4. Inside the if block, the program converts the ASCII value to its corresponding character using a = chr(i).
  5. The program then prints the character without moving to a new line using print(a, end="").
  6. If the ASCII values of i and j are not equal (when not on the main diagonal), the program prints a space using print(" ", end="").
  7. After the first nested loop finishes, there's a second nested loop for k in range(68, 64, -1):. This loop iterates in reverse from ASCII value 68 (character 'D') to 64 (character '@'), going downwards. This loop is responsible for printing the characters in the second part of each row.
  8. Inside the second loop, there's another if condition: if(i == k):. This checks if the ASCII value of the outer loop variable is equal to the current value of k.
  9. Inside the if block, the program again converts the ASCII value to its corresponding character using a = chr(i).
  10. The program then prints the character without moving to a new line using print(a, end="").
  11. If the ASCII values of i and k are not equal (when not on the main diagonal), the program prints a space using print(" ", end="").
  12. After both nested loops finish, a print() statement is used to move to the next line, starting a new row in the pattern.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (Python Alphabet Pattern 31) please comment here. I will help you immediately.

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