Java Number Pattern 62

Posted in Java Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 137 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

Java Number Pattern 62

Here`s a program that prints the above number pattern using Java Programming:

Demo.java

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public class Demo
{
 public static void main(String[] args)
 {
  int[][] a = new int[10][10];
  int i, j, low=0, high=9, n=1;
  for(i=0; i<5; i++, low++, high--)
  {
   for(j=low; j<=high; j++, n++)
    a[i][j] = n;
   for(j=low+1; j<=high; j++, n++)
    a[j][high] = n;
   for(j=high-1; j>=low; j--, n++)
    a[high][j] = n;
   for(j=high-1; j>low; j--, n++)
    a[j][low] = n;
  }
  System.out.println("\t\tPerfect Square Spiral\n");
  for(i=0; i<10; i++)
  {
   System.out.println();
   for(j=0; j<10; j++)
    System.out.format("%4d", a[i][j]);
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

1    2    3    4    5    6    7    8    9   10
36  37   38   39   40   41   42   43   44   11
35  64   65   66   67   68   69   70   45   12
34  63   84   85   86   87   88   71   46   13
33  62   83   96   97   98   89   72   47   14
32  61   82   95  100   99   90   73   48   15
31  60   81   94   93   92   91   74   49   16
30  59   80   79   78   77   76   75   50   17
29  58   57   56   55   54   53   52   51   18
28  27   26   25   24   23   22   21   20   19

🧠 How the Program Works

Let's break down the logic behind the code:

The program defines a class named Demo.
Inside the class, there is a main method, which serves as the entry point of the program.
The program creates a 10x10 integer array named a to hold the spiral pattern.
It declares integer variables i, j, low, high, and n. i and j are loop control variables, low and high represent the current bounds of the spiral, and n is used to populate the array with numbers.
The outer loop (for(i=0; i<5; i++, low++, high--)) runs five times. This loop controls the creation of each spiral layer from the outermost to the innermost.
Inside this loop, there are four nested loops that handle the four sides of the spiral layer:
1. The first loop (for(j=low; j<=high; j++, n++)) fills the top side of the layer.
2. The second loop (for(j=low+1; j<=high; j++, n++)) fills the right side of the layer.
3. The third loop (for(j=high-1; j>=low; j--, n++)) fills the bottom side of the layer.
4. The fourth loop (for(j=high-1; j>low; j--, n++)) fills the left side of the layer.
After filling the current layer, the outer loop increments low (to move inward from the top) and decrements high (to move inward from the right).
Once all spiral layers are filled, the program prints the matrix in a formatted manner.
It prints a header message: "\t\tPerfect Square Spiral".
It enters a nested loop to iterate through each element of the matrix and prints them in a formatted way using System.out.format("%4d", a[i][j]).
Finally, the program prints a newline character to separate rows.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!