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Java Number Programs

Java Number Pattern 29

Posted in Java Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 107 - Views
⏳ 4 mins
💬 1 Comment
Java Number Pattern 29

Photo Credit to CodeToFun

Java Number Pattern 29

Here`s a program that prints the above number pattern using Java Programming:

Demo.java
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public class Demo
{
 public static void main(String[] args)
 {
  int i, j, k;
  for(i=1; i<=5; i++)
  {
   for(j=1; j<=5; j++)
   {
    if(j <= i)
     System.out.print(j);
    else
     System.out.print(" ");
   }
   for(k=5; k>=1; k--)
   {
    if(k > i)
     System.out.print(" ");
    else
     System.out.print(k);
   }
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
1        1
12      21
123    321
1234  4321
1234554321

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program starts with defining a class named Demo.
  2. The main method is the entry point of the program. It accepts an array of strings args, although in this case, it's not used.
  3. Three integer variables i, j, and k are declared to control the loops.
  4. The outer loop (for loop) runs from i = 1 to i <= 5. This loop controls the rows of the pattern.
  5. Inside the outer loop, there are two nested loops:
    • The first nested loop (for loop with variable j) runs from j = 1 to j <= 5. This loop controls the printing of numbers in the left half of each row.
    • Inside this loop, there's an if-else condition. If j is less than or equal to i, it prints the value of j. Otherwise, it prints a space.
    • The result is that in the left half of the row, the loop prints the numbers 1 to i, followed by spaces.
    • The second nested loop (for loop with variable k) runs from k = 5 to k >= 1. This loop controls the printing of numbers in the right half of each row.
    • Inside this loop, there's an if-else condition. If k is greater than i, it prints a space. Otherwise, it prints the value of k.
    • The result is that in the right half of the row, the loop prints the numbers 5 to i, in decreasing order, followed by spaces.
  6. After both nested loops have executed, a newline character is printed using System.out.println() to move to the next row.
  7. The outer loop repeats this process for all rows, incrementing i in each iteration.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
11 months ago

If you have any doubts regarding this article (Java Number Pattern 29) please comment here. I will help you immediately.

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