Python Program to Check Pronic Number

Posted in Python Tutorial

Updated on Jan 11, 2024

By Mari Selvan

👁️ 57 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

🙋 Introduction

In the realm of programming, mathematical patterns and properties often become interesting challenges. One such intriguing concept is the "Pronic Number."

A pronic number, also known as a rectangular number, oblong number, or heteromecic number, is the product of two consecutive integers.

In this tutorial, we will dive into a Python program designed to check whether a given number is a pronic number or not.

📄 Example

Now, let's explore the Python code that checks whether a given number is a pronic number or not.

is_pronic.py

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import math

# Function to check if a number is a pronic number
def is_pronic(num):
    sqrt_num = int(math.sqrt(num))
    return sqrt_num * (sqrt_num + 1) == num

# Driver program
if __name__ == "__main__":
    # Replace this value with your desired number
    number = 12

    # Check if the number is a pronic number
    if is_pronic(number):
        print(f"{number} is a pronic number.")
    else:
        print(f"{number} is not a pronic number.")

💻 Testing the Program

To test the program with different numbers, simply replace the value of number in the if __name__ == "__main__": block.

Output

12 is a pronic number.

Run the script to check if the given number is a pronic number.

🧠 How the Program Works

The program defines a function is_pronic that takes a number as input and returns True if the number is a pronic number and False otherwise.
Inside the function, it calculates the integer square root of the input number.
It checks whether the product of the square root and the square root incremented by 1 equals the input number. If yes, the number is a pronic number.
The driver program tests the function with a sample number and prints the result.

📏 Between the Given Range

Let's take a look at the python code that checks for pronic numbers in the range from 1 to 20.

is_pronic.py

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# Function to check if a number is Pronic
def is_pronic(number):
    for i in range(1, int(number**0.5) + 1):
        if i * (i + 1) == number:
            return True
    return False

# Range to check for Pronic numbers
start_range = 1
end_range = 20

# Display Pronic numbers in the specified range
pronic_numbers = [num for num in range(start_range, end_range + 1) if is_pronic(num)]

print(f"Pronic Numbers in the range {start_range} to {end_range}:\n{' '.join(map(str, pronic_numbers))}")

💻 Testing the Program

Output

Pronic Numbers in the range 1 to 20:
2 6 12 20

Simply run the Python script to see the Pronic numbers in the range from 1 to 20.

🧠 How the Program Works

The program defines a function is_pronic to check if a given number is a Pronic number.
Inside the function, it iterates through each number up to the square root of the input number, checking if n×(n+1) is equal to the given number.
The main section then defines the range from 1 to 20 and identifies Pronic numbers within that range.
The result is displayed in the specified output format.

🧐 Understanding the Concept of Pronic Numbers

Before delving into the code, let's take a moment to understand the concept of pronic numbers.

A pronic number is a product of two consecutive integers, and it has applications in various mathematical and geometric contexts.

A pronic number, denoted by P_n, is a number of the form P_n=n × (n+1) where n is a non-negative integer. The sequence of pronic numbers starts as 0, 2, 6, 12, 20, and so on.

For example, let's take n = 3. The corresponding pronic number would be P₃ = 3x(3+1) = 12.