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Python Program to Check for a Cube Number

Posted in Python Tutorial
Updated on Oct 31, 2024
By Mari Selvan
πŸ‘οΈ 86 - Views
⏳ 4 mins
πŸ’¬ 1 Comment
Python Program to Check for a Cube Number

Photo Credit to CodeToFun

πŸ™‹ Introduction

In the realm of programming, mathematical properties of numbers often lead to interesting and practical applications. One such property is being a cube number. A cube number is an integer that is the cube of an integer.

In this tutorial, we'll delve into a Python program that efficiently checks whether a given number is a perfect cube.

πŸ“„ Example

Let's take a look at the Python code that accomplishes this functionality.

is_perfect_cube.py
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def is_perfect_cube(number):
    # Calculate the cube root of the number
    cube_root = number ** (1/3)

    # Check if the cube root is close to an integer
    return abs(cube_root - round(cube_root)) < 1e-10

# Driver program
if __name__ == "__main__":
    # Replace this value with your desired number
    number = 27

    # Check if the number is a perfect cube
    if is_perfect_cube(number):
        print(f"{number} is a perfect cube.")
    else:
        print(f"{number} is not a perfect cube.")

πŸ’» Testing the Program

To test the program with different numbers, simply replace the value of the number variable in the if __name__ == "__main__": block.

Output
27 is a perfect cube.

Run the script to check if the number is a perfect cube.

🧠 How the Program Works

  1. The program dexfines a function is_perfect_cube that takes an integer as input and returns True if it is a perfect cube, and False otherwise.
  2. Inside the function, it calculates the cube root of the number using the exponentiation operator.
  3. It then checks if the cube root is close to an integer using a tolerance value (1e-10 in this case).
  4. The if __name__ == "__main__": block initializes a variable with a number and calls the is_perfect_cube function to determine if it's a perfect cube.

πŸ“ Between the Given Range

Let's dive into the Python code that checks for cube numbers in the range from 1 to 50.

is_cube_number.py
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# Function to check if a number is a cube number
def is_cube_number(num):
    cube_root = round(num ** (1 / 3))
    return cube_root ** 3 == num

# Main program to find cube numbers in the range 1 to 50
def find_cube_numbers():
    print("Cube numbers in the range 1 to 50:")

    for i in range(1, 51):
        if is_cube_number(i):
            print(i, end=" ")

# Call the function to find cube numbers
find_cube_numbers()

πŸ’» Testing the Program

Output
Cube numbers in the range 1 to 50:
1 8 27

Run the script to see the cube numbers in the specified range.

🧠 How the Program Works

  1. The program defines a function is_cube_number that checks if a given number is a cube number.
  2. Inside the function, it calculates the cube root of the number and checks if raising it to the power of 3 results in the original number.
  3. The main program, find_cube_numbers, iterates through the range from 1 to 50 and prints the cube numbers.

🧐 Understanding the Concept of Cube Number

A cube number is the result of raising an integer to the power of 3. For example, 2 * 2 * 2 = 8, so 8 is a cube number.

🎒 Optimizing the Program

The provided program is straightforward, but you might consider optimizing it further. For instance, you can explore alternative methods for checking if a number is a cube number without using the cbrt function.

Feel free to incorporate and modify this code as needed for your specific use case. Happy coding!

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Author

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πŸ‘‹ Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
10 months ago

If you have any doubts regarding this article (Python Program to Check for a Cube Number), please comment here. I will help you immediately.

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