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JavaScript Program to Check Odd Number

Updated on Jan 11, 2024
By Mari Selvan
πŸ‘οΈ 102 - Views
⏳ 4 mins
πŸ’¬ 1 Comment
JavaScript Program to Check Odd Number

Photo Credit to CodeToFun

πŸ™‹ Introduction

In the realm of programming, dealing with numbers is a fundamental task. One common requirement is checking whether a given number is odd or not.

An odd number is an integer that is not exactly divisible by 2 and leaves a remainder of 1 when divided by 2.

In this tutorial, we will explore a JavaScript program designed to check whether a given number is odd. The program involves using the modulo operator to determine if the number is not divisible by 2.

πŸ“„ Example

Let's delve into the JavaScript code that accomplishes this task.

isOdd.js
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// Function to check if a number is odd
function isOdd(number) {
  // If the remainder is 1, the number is odd
  return number % 2 !== 0;
}

// Driver program
// Replace this value with the number you want to check
const number = 15;

// Call the function to check if the number is odd
if (isOdd(number)) {
  console.log(`${number} is an odd number.`);
} else {
  console.log(`${number} is not an odd number.`);
}

πŸ’» Testing the Program

To test the program with different numbers, modify the value of number in the code.

Output
15 is an odd number.

🧠 How the Program Works

  1. The program defines a function isOdd that takes a number as input and returns true if the number is odd, and false otherwise.
  2. Replace the value of number in the main program with the desired number you want to check.
  3. The program calls the isOdd function and prints the result using console.log.

πŸ“ Between the Given Range

Let's take a look at the javascript code that checks and displays odd numbers in the specified range.

checkOddNumbersInRange.js
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// Function to check if a number is odd
function isOdd(number) {
  return number % 2 !== 0;
}

// Driver program
function checkOddNumbersInRange() {
  let oddNumbers = [];

  // Loop through the range from 1 to 10
  for (let i = 1; i <= 10; i++) {
    if (isOdd(i)) {
      oddNumbers.push(i);
    }
  }

  return oddNumbers;
}

// Call the function to get odd numbers in the range
const oddNumbersInRange = checkOddNumbersInRange();

// Output the result
console.log(`Odd Numbers in the range 1 to 10: ${oddNumbersInRange.join(' ')}`);

πŸ’» Testing the Program

Output
Odd Numbers in the range 1 to 10:
1 3 5 7 9

The range for this program is fixed from 1 to 10. To test the program, simply run it.

🧠 How the Program Works

  1. The program defines a function isOdd that checks whether a given number is odd.
  2. The checkOddNumbersInRange function loops through the range from 1 to 10, calls isOdd to determine if each number is odd, and collects the odd numbers in an array.
  3. The result is then output in the specified format using console.log.

🧐 Understanding the Concept of Odd Number

Before delving into the code, let's understand the concept of odd numbers. An odd number is an integer that is not exactly divisible by 2. In other words, when an odd number is divided by 2, the remainder is 1.

🎒 Optimizing the Program

While the provided program is effective, consider exploring and implementing alternative approaches or optimizations for checking odd numbers.

Feel free to incorporate and modify this code as needed for your specific use case. Happy coding!

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Author

author
πŸ‘‹ Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
8 months ago

If you have any doubts regarding this article (JavaScript Program to Check Odd Number), please comment here. I will help you immediately.

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