Java Program to check Natural Number

Posted in Java Tutorial

Updated on Oct 30, 2024

By Mari Selvan

👁️ 118 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

🙋 Introduction

In the realm of programming, understanding and validating numbers is a fundamental task. One common classification is that of natural numbers.

A natural number is a positive integer greater than zero.

In this tutorial, we will explore a straightforward Java program that checks whether a given number is a natural number or not.

📄 Example

Let's dive into the Java code that accomplishes this functionality.

isNaturalNumber.js

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public class CheckNaturalNumber {

// Function to check if a number is a natural number
static boolean isNaturalNumber(int num) {
  return num > 0;
}

// Driver program
public static void main(String[] args) {
  // Replace this value with your desired number
  int number = 42;

  // Check if the number is a natural number
  if (isNaturalNumber(number)) {
    System.out.println(number + " is a natural number.");
  } else {
    System.out.println(number + " is not a natural number.");
  }
}
}

💻 Testing the Program

To test the program with different numbers, replace the value of number in the main method.

Output

42 is a natural number.

Compile and run the program to see if the given number is a natural number.

🧠 How the Program Works

The program defines a class CheckNaturalNumber containing a static method isNaturalNumber that takes a number as input and returns true if it's a natural number (greater than 0) and false otherwise.
In the main method, replace the value of number with the desired number.
The program then checks if the number is a natural number using the isNaturalNumber method.
It prints whether the number is a natural number or not based on the result.

🤔 Considerations

The program assumes the input number is an integer.
For user input scenarios, additional validation may be required to handle non-integer inputs.

📏 Between the Given Range

Let's dive into the java code that checks and displays natural numbers in the range from 1 to 10.

NaturalNumberChecker.java

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public class NaturalNumberChecker {

  // Function to check and list natural numbers in the range 1 to 10
  static void checkAndListNaturalNumbers() {
    System.out.print("Natural Numbers in the range 1 to 10: ");

    // Iterate through the range
    for (int i = 1; i <= 10; i++) {
      System.out.print(i + " ");
    }

    System.out.println();
  }

  // Driver program
  public static void main(String[] args) {
    // Call the function to check and list natural numbers
    checkAndListNaturalNumbers();
  }
}

💻 Testing the Program

Output

Natural Numbers in the range 1 to 10:
1 2 3 4 5 6 7 8 9 10

To test the program, compile and run it. The output will display the natural numbers in the range 1 to 10.

🧠 How the Program Works

The program defines a class NaturalNumberChecker containing a static method checkAndListNaturalNumbers that prints natural numbers in the range 1 to 10.
Inside the method, it uses a for loop to iterate through the specified range and prints each natural number.
The main method calls the function to check and list natural numbers.

🧐 Understanding the Concept of Natural Numbers

Natural numbers are a set of positive integers that start from 1 and continue indefinitely. They are often used for counting and ordering.

In this program, we check whether a given number is a natural number by verifying if it is greater than zero.

🎉 Conclusion

This java program serves as a foundational example for checking whether a number is a natural number or not. Understanding the characteristics of natural numbers and incorporating such checks can be essential in various programming scenarios

Feel free to incorporate and modify this code as needed for your specific use case. Happy coding!