Java Alphabet Pattern 33

Posted in Java Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 72 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

Java Alphabet Pattern 33

Here`s a program that prints the above alphabet pattern using Java Programming:

Demo.java

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public class Demo
{
 public static void main(String[] args)
 {
  int i, j, k;
  for(i=65; i<=69; i++)
  {
   for(j=69; j>=65; j--)
   {
    if(i == j)
     System.out.format("%c", j);
    else
     System.out.print(" ");
   }
   for(k=66; k<=69; k++)
   {
    if(i == k)
     System.out.format("%c", k);
    else
     System.out.print(" ");
   }
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

    A
   B B
  C   C
 D     D
E       E

🧠 How the Program Works

Let's break down the logic behind the code:

The program defines a class named Demo.
Inside the Demo class, there's a main method, which serves as the entry point of the program. It takes an array of strings args as a parameter, although in this program, args is not used.
Three integer variables i, j, and k are declared to be used as loop counters.
The outer loop (for(i=65; i<=69; i++)) runs from i equal to 65 (which corresponds to the ASCII value of 'A') to i equal to 69 (which corresponds to the ASCII value of 'E'). This loop controls the rows of the diamond pattern.
Inside the outer loop, there are two nested loops:
- The first nested loop (for(j=69; j>=65; j--)) runs from j equal to 69 (ASCII 'E') down to j equal to 65 (ASCII 'A'). This loop is responsible for printing spaces or characters in the first half of each row.
- The second nested loop (for(k=66; k<=69; k++)) runs from k equal to 66 (ASCII 'B') to k equal to 69 (ASCII 'E'). This loop is responsible for printing spaces or characters in the second half of each row.
Inside each nested loop, there's an if statement that checks whether i is equal to the current loop counter (j or k). If i is equal to the loop counter, it prints the character represented by the current value of j or k using System.out.format("%c", j); or System.out.format("%c", k);. If i is not equal to the loop counter, it prints a space using System.out.print(" ");.
After printing the characters or spaces in both halves of a row, the program prints a newline character using System.out.println();, which moves the cursor to the next line for the next row.
The outer loop repeats these steps for each row, incrementing the value of i from 'A' to 'E'.
When the program finishes running, it will have printed a diamond-shaped pattern of characters where the characters 'A' to 'E' are arranged in the shape of a diamond, with spaces in between.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!