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Java Alphabet Pattern 30

Posted in Java Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 127 - Views
⏳ 4 mins
💬 1 Comment
Java Alphabet Pattern 30

Photo Credit to CodeToFun

Java Alphabet Pattern 30

Here`s a program that prints the above alphabet pattern using Java Programming:

Demo.java
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public class Demo
{
 public static void main(String[] args)
 {
  int i, j, k;
  for(i=65; i<=69; i++)
  {
   for(j=i; j>65; j--)
    System.out.format("%c", j);
   for(k=65; k<=134-i; k++)
    System.out.format("%c", k);
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
ABCDE
BABCD
CBABC
DCBAB
EDCBA

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program starts with the declaration of a class named Demo.
  2. Inside the Demo class, there is a main method, which serves as the entry point for the program.
  3. Inside the main method, three integer variables are declared: i, j, and k. These variables will be used as loop counters.
  4. The outermost loop runs from i=65 to i<=69. The value of 65 corresponds to the ASCII character 'A', and 69 corresponds to 'E'. This loop controls the rows of the pattern, and it will execute 5 times.
  5. Inside the outer loop, there are two nested loops:
    • The first nested loop (for(j=i; j>65; j--)) is responsible for printing characters in descending order. It starts with the current value of i and decrements j until it reaches 65, which is the ASCII value of 'A'. It uses System.out.format to print each character. For example, when i=65, it will print 'A', when i=66, it will print 'BA', and so on.
    • The second nested loop (for(k=65; k<=134-i; k++)) is responsible for printing characters in ascending order. The loop starts with the value 65 and goes up to 134 - i. The value 134 - i ensures that the characters printed in this loop are different from those printed in the first nested loop. It also uses System.out.format to print each character.
  6. After both nested loops finish execution, a newline character is printed using System.out.println(). This moves the program's output to the next line for the next row of the pattern.
  7. The outer loop continues to run until i reaches 69, at which point the program terminates.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (Java Alphabet Pattern 30), please comment here. I will help you immediately.

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