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C++ Program to Check Odd Number

Posted in C++ Tutorial
Updated on Oct 06, 2024
By Mari Selvan
πŸ‘οΈ 141 - Views
⏳ 4 mins
πŸ’¬ 1 Comment
C++ Program to Check Odd Number

Photo Credit to CodeToFun

πŸ™‹ Introduction

In the realm of programming, dealing with numbers is a fundamental task. One common requirement is checking whether a given number is odd or not.

An odd number is an integer that is not exactly divisible by 2 and leaves a remainder of 1 when divided by 2.

In this tutorial, we will explore a C++ program designed to check whether a given number is odd. The program involves using the modulo operator to determine if the number is not divisible by 2.

πŸ“„ Example

Let's delve into the C++ code that accomplishes this task.

odd.cpp
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#include <iostream>

class OddNumberChecker {
  public:
    // Function to check if a number is odd
    static bool isOdd(int number) {
      // If the remainder is 1, the number is odd
      return number % 2 != 0;
    }
};

// Driver program
int main() {
  // Replace this value with the number you want to check
  int number = 15;

  // Call the function to check if the number is odd
  if (OddNumberChecker::isOdd(number))
    std::cout << number << " is an odd number." << std::endl;
  else
    std::cout << number << " is not an odd number." << std::endl;

  return 0;
}

πŸ’» Testing the Program

To test the program with different numbers, modify the value of number in the main function.

Output
15 is an odd number.

🧠 How the Program Works

  1. The program defines a class OddNumberChecker containing a static method isOdd that takes an integer number as input and returns true if the number is odd, and false otherwise.
  2. Inside the main function, replace the value of number with the desired number you want to check.
  3. The program calls the isOdd method and prints the result using std::cout.

πŸ“ Between the Given Range

Let's take a look at the C++ code that checks and displays odd numbers in the specified range.

checkOddNumbers.cpp
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#include <iostream>

// Function to check and display odd numbers in the range 1 to 10
void checkOddNumbers() {
  std::cout << "Odd Numbers in the range 1 to 10: ";

  for (int i = 1; i <= 10; ++i) {
    // Check if the current number is odd
    if (i % 2 != 0) {
      std::cout << i << " ";
    }
  }

  std::cout << std::endl;
}

// Driver program
int main() {
  // Call the function to check and display odd numbers
  checkOddNumbers();

  return 0;
}

πŸ’» Testing the Program

Output
Odd Numbers in the range 1 to 10:
1 3 5 7 9

The range for this program is fixed from 1 to 10. To test the program, simply compile and run it.

🧠 How the Program Works

  1. The program defines a function checkOddNumbers that iterates through the numbers from 1 to 10.
  2. For each iteration, it checks if the current number is odd using the modulo operator.
  3. If the number is odd, it is displayed.

🧐 Understanding the Concept of Odd Number

Before delving into the code, let's understand the concept of odd numbers. An odd number is an integer that is not exactly divisible by 2. In other words, when an odd number is divided by 2, the remainder is 1.

🎒 Optimizing the Program

While the provided program is effective, consider exploring and implementing alternative approaches or optimizations for checking odd numbers.

Feel free to incorporate and modify this code as needed for your specific use case. Happy coding!

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Author

author
πŸ‘‹ Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
11 months ago

If you have any doubts regarding this article (C++ Program to Check Odd Number), please comment here. I will help you immediately.

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