Shape Rule
Continuous k++
Row 1 prints 1, row 2 prints 2 3, row 3 prints 4 5 6, and so on without restarting.

The continuous number triangle uses a running counter k so digits keep increasing across rows — a natural step after the fill-with-5 pattern in Program 19. This tutorial covers the shape rule, counter logic, a live preview, algorithm steps, worked C++ examples, edge cases, and complexity.
Continuous k++
Row 1 prints 1, row 2 prints 2 3, row 3 prints 4 5 6, and so on without restarting.
1..rows
for (i = 1; i <= rows; i++) makes row i print i numbers.
k++ each print
cout << k++ << " " prints k then increments — value carries to the next row.
Same line / next line
Numbers use cout << k++ << " "; end each row with cout << "\n".
1–15 rows
Pick a row count and draw the continuous counter triangle instantly in the browser.
Complexity
Total prints = rows(rows+1)/2; extra memory stays O(1).
A continuous number triangle prints an ascending counter across rows — numbers never restart at 1 on each new line. With rows = 4, the output is 1, 2 3, 4 5 6, 7 8 9 10.
In C++ you declare k = 1 once, print k++ in the inner loop for i iterations per row, then cout << "\n" ends each row.
It introduces a running counter variable — a key step after Program 19 and before jump-number patterns.
Declare k = 1 once before both loops.
Print then increment — sequence continues across rows.
cout << k++ << " " in the inner loop; cout << "\n" after.
Follow Program 19; continue to Program 21 (jump number triangle).
In short: set k = 1 once, for each row i print k++ for i numbers, then call cout << "\n".
Given a positive integer rows, print a continuous number triangle: row i prints i numbers from a running counter k that starts at 1 and increments with k++ on every print.
// rows = 4 (conceptual shape)
// 1
// 2 3
// 4 5 6
// 7 8 9 10 | Item | Type | Description |
|---|---|---|
rows | int | Number of triangle lines to print (typically ≥ 1). |
k | int | Running counter — declared once, incremented each print. |
| Printed output | text | Row i has i spaced numbers — continuous sequence. |
k = 1
for i from 1 to rows:
for j from 1 to i:
print k then k++
print newline | Approach | Idea | Best for |
|---|---|---|
| Running counter k++ | 1, 2 3, 4 5 6, … | Learning and interviews |
| User-input rows | cin >> rows; | Flexible console programs |
| Custom start k | k = 10 before loops | Shift the whole sequence |
| Goal | Pattern |
|---|---|
| Walk each row | for (i = 1; i <= rows; i++) |
| Init counter | int k = 1; before both loops |
| Print and step | cout << k++ << " "; |
| End the row | cout << "\n"; |
| Custom start | int k = 10; to shift sequence |
| User input | cin >> rows; |
Same continuous triangle — different ways to control the counter.
counterPrint k then increment — sequence continues
k = 1Before both loops — not inside outer loop
k = 10Shift start value in Example 3
no resetDo not reset k each row for continuous output
Reach for this pattern when teaching running counters and continuous sequences inside nested loops.
Natural follow-up after Program 19 — introduces a single running counter.
Outer/inner bound practice with an immediate visual check.
Combine loops with cin for a flexible row count.
Compare Program 19 (fill-with-5) and Program 21 (jump number triangle) next.
This is a console teaching pattern — not how you build modern app screens.
Key benefit: one small program that locks in nested loops, output sequencing, and O(n²) thinking.
Choose a row count between 1 and 15 and draw the continuous number triangle in the browser.
Three complete C++ programs — fixed row count, user input, and custom start value for k. Click View Output to reveal sample console results.
Print four rows of the continuous counter triangle with k++.
rows = 4Hard-coded height — ideal for first demos and screenshots.
#include <iostream>
using namespace std;
int main() {
int rows = 4;
int i, j;
int k = 1;
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j)
cout << k++ << " ";
cout << "\n";
}
return 0;
} When i = 1, k prints once as 1. When i = 2, k prints 2 then 3. When i = 4, k runs from 7 to 10 — the counter never resets. cout << "\n" after the inner loop starts the next row.
Read the row count with cin instead of hard-coding 4.
Read rows with cin >> rows (check cin.fail() in real apps); k still starts at 1.
#include <iostream>
using namespace std;
int main() {
int rows;
int i, j;
int k = 1;
cout << "Enter the number of rows: ";
cin >> rows;
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j)
cout << k++ << " ";
cout << "\n";
}
return 0;
} Same nested-loop core as Example 1; only the source of rows changes. k is still declared once before the loops. Non-numeric input sets cin’s fail bit if you ignore errors — always validate in safer labs.
Start the counter from a value other than 1.
k = 10Shift the whole sequence by starting k at 10 instead of 1.
#include <iostream>
using namespace std;
int main() {
int rows = 4;
int i, j;
int k = 10;
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j)
cout << k++ << " ";
cout << "\n";
}
return 0;
} Change only the initial value of k — the inner loop and k++ logic stay the same. The sequence continues from 10 instead of 1.
#include <iostream> brings in cout and cin. Set rows and k = 1.
for (i = 1; i <= rows; i++) makes row i print i numbers.
cout << k++ << " " prints k then increments — value carries to the next row.
cout << "\n" ends the row so the next outer iteration starts fresh.
Total prints: rows(rows+1)/2 — O(n²) time, O(1) extra memory.
rows = 4Trace each outer-loop value of i, the starting k, and the numbers printed on each row.
i | Start k | Numbers printed | Row output |
|---|---|---|---|
1 | 1 | 1 | 1 |
2 | 2 | 2, 3 | 2 3 |
3 | 4 | 4, 5, 6 | 4 5 6 |
4 | 7 | 7, 8, 9, 10 | 7 8 9 10 |
Total number prints: 1 + 2 + 3 + 4 = 10 = 4×5/2.
Where this tiny pattern (and its loop structure) shows up beyond the homework prompt.
Clearest visual proof that outer and inner bounds interact.
Example: change j <= i and watch the shape change.
Foundation for inverted, pyramid, diamond, and hollow variants.
Example: use (i + j) % 2 for row+column parity grids.
Practice cout << k++ vs row newline without complex math.
Example: put cout << "\n" inside the inner loop by mistake.
Swap digits for letters, stars, or spaced output once the loop works.
Example: print j + " " for spaced digits on each row.
Triangular totals make O(n²) concrete for beginners.
Example: count printed digits for n = 10 still → 55.
Pair the pattern with cin.fail() checks and positive-row checks.
Example: reject rows <= 0 and re-prompt.
Pro Tip: when an interviewer asks for patterns, explain the outer/inner roles first — then write the loops. The story matters as much as the code.
Why this pattern earns a permanent spot in beginner C++ courses.
Wrong bounds show up immediately as a broken staircase.
Only loops and console output — no arrays or math libraries.
Invert, center, hollow, or change the fill character with small edits.
Streaming output needs no storage beyond loop counters.
Pro Tip: learn k = 1 before the loops first; compare with custom start in Example 3.
Small habits that keep number-pattern code clean.
Declare k once before both loops — not inside the outer loop.
cinCheck cin.fail() so bad input does not leave rows unset.
Only call cout << "\n" after the inner loop finishes the row.
Write row i, start k, and each k++ step before coding.
Trace rows = 4 on paper before coding larger demos.
Pro Tip: if the output is a vertical list of single digits per line, you almost certainly put cout << "\n" inside the inner loop.
Mistakes that commonly break continuous number patterns.
Each digit lands on its own line — you get a column, not a triangle.
→ Use cout << k++ << " "; cout << "\n" only after the inner loop.
k resets each row and the sequence restarts at 1.
→ Declare int k = 1; once before both loops.
Incrementing in the wrong place skips or duplicates numbers.
→ Use post-increment inside cout << k++ << " ".
Omitting cout << "\n" glues every number onto one endless line.
→ Always end the row after the inner loop.
Letters or empty input leave rows unset.
→ Check cin.fail() and re-prompt on failure.
Check these inputs before calling the solution done.
Output is just 1 on one line.
Outer loop never runs — print nothing or show a message.
rows < 0Treat as invalid; re-prompt instead of silent empty output.
Output grows as n² characters — fine for labs, noisy for huge n.
Unchecked cin leaves rows unset — check cin.fail().
Declaring k inside the outer loop restarts the sequence — not continuous.
Without k++, the same number prints repeatedly on each row.
Try these variations to lock in the pattern.
k inside outer looprows(rows+1)/2 — O(n²) for n rows.cout << k++ << " " stays on the line; cout << "\n" advances — mix them carefully.rows > 0 for interactive programs; rows = 1 should print a single 1.Quick Takeaway: declare k = 1 once, print k++ for i numbers per row, then break the line.
| Program | Time | Extra space |
|---|---|---|
| Nested loops (Examples 1–2) | O(rows²) | O(1) |
| Custom start (Example 3) | O(rows²) | O(1) |
The continuous number triangle is a compact lesson in running counters: declare k once, print k++ in the inner loop, and let the sequence continue across rows. Master the fixed-rows version, then try user input and a custom start value.
Practice the three examples above, then continue to Program 21 for the jump number triangle.
Keep k outside the outer loop — use k++ inside cout << k++ << " " and validate rows when reading input.
k = 1 before both loopscout << k++ << " " in the inner looprows ≥ 1 for interactive programscin.fail() before using rowscout << "\n" inside the inner digit loopk inside the outer loopk++ after each printrows = 1 edge casePrint the pattern the beginner-friendly way.
k++ continuous
DefinitionOnce before loops
CodePrint then increment
CodeRow i prints i nums
ShapeO(n²) time
AnalysisA single counter k starts at 1 and increments with k++ on every print — numbers continue across rows instead of restarting. Total prints still equal n(n+1)/2 for n rows.
Move on to the jump number triangle in the C++ number-pattern series.
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