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C++ Program to Check Even Number

Posted in C++ Tutorial
Updated on Oct 27, 2024
By Mari Selvan
πŸ‘οΈ 231 - Views
⏳ 4 mins
πŸ’¬ 1 Comment
C++ Program to Check Even Number

Photo Credit to CodeToFun

πŸ™‹ Introduction

In the realm of programming, dealing with numbers is a fundamental task. One common requirement is checking whether a given number is even or not. An even number is an integer that is exactly divisible by 2 without leaving a remainder.

In this tutorial, we will explore a C++ program designed to check whether a given number is even. The program involves using the modulo operator to determine if the number is divisible by 2.

πŸ“„ Example

Let's delve into the C++ code that accomplishes this task.

EvenNumberChecker.cpp
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#include <iostream>

class EvenNumberChecker {
  public:
    // Function to check if a number is even
    static bool isEven(int number) {
      // If the remainder is zero, the number is even
      return number % 2 == 0;
    }
};

// Driver program
int main() {
  // Replace this value with the number you want to check
  int number = 10;

  // Call the function to check if the number is even
  if (EvenNumberChecker::isEven(number))
    std::cout << number << " is an even number." << std::endl;
  else
    std::cout << number << " is not an even number." << std::endl;

  return 0;
}

πŸ’» Testing the Program

To test the program with different numbers, modify the value of number in the main function.

Output
10 is an even number.

🧠 How the Program Works

  1. The program defines a class EvenNumberChecker containing a static method isEven that takes an integer number as input and returns true if the number is even, and false otherwise.
  2. Inside the main function, replace the value of number with the desired number you want to check.
  3. The program calls the isEven method and prints the result using std::cout.

πŸ“ Between the Given Range

Let's take a look at the C++ code that checks for even numbers in the specified range.

isEven.cpp
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#include <iostream>

// Function to check if a number is even
bool isEven(int number) {
  return (number % 2 == 0);
}

// Function to display even numbers in a range
void displayEvenNumbersInRange(int start, int end) {
  std::cout << "Even numbers in the range " << start << " to " << end << ":\n";

  for (int i = start; i <= end; ++i) {
    if (isEven(i)) {
      std::cout << i << " ";
    }
  }

  std::cout << std::endl;
}

// Driver program
int main() {
  // Fixed range from 1 to 10
  int start = 1;
  int end = 10;

  // Call the function to display even numbers in the range
  displayEvenNumbersInRange(start, end);

  return 0;
}

πŸ’» Testing the Program

Output
Even numbers in the range 1 to 10:
2 4 6 8 10

Compile and run the program to see the even numbers in the specified range.

🧠 How the Program Works

  1. The program defines a function isEven that takes a number as input and returns true if the number is even, and false otherwise.
  2. The function displayEvenNumbersInRange takes a start and end value and prints the even numbers in that range using the isEven function.
  3. The main function sets a fixed range from 1 to 10 and calls the displayEvenNumbersInRange function.

🧐 Understanding the Concept of Even Number

Before delving into the code, let's understand the concept of even numbers. An even number is an integer that is exactly divisible by 2.

In other words, when an even number is divided by 2, the remainder is zero.

🎒 Optimizing the Program

While the provided program is straightforward, consider exploring and implementing alternative approaches or optimizations for checking even numbers.

Feel free to incorporate and modify this code as needed for your specific use case. Happy coding!

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Author

author
πŸ‘‹ Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
11 months ago

If you have any doubts regarding this article (C++ Program to Check Even Number) please comment here. I will help you immediately.

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