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C Alphabet Pattern 22

Posted in C Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 130 - Views
⏳ 4 mins
💬 1 Comment
C Alphabet Pattern 22

Photo Credit to CodeToFun

C Alphabet Pattern 22

Here`s a program that prints the above alphabet pattern using C Programming:

example.c
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#include <stdio.h>

int main() {
  int i, j, k;
  k = 65;
  for (i = 65; i <= 69; i++) {
    for (j = 69; j >= 65; j--) {
      if (j > i)
        printf("  ");
      else
        printf("%2c", k++);
    }
    printf("\n");
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
        A
      B C
    D E F
  G H I J
K L M N O

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program starts by including the necessary header file stdio.h, which provides input/output functions like printf.
  2. The main() function is the entry point of the program.
  3. Inside the main() function, three integer variables i, j, and k are declared. These variables will be used for looping and storing values.
  4. The variable k is assigned the ASCII value of the character 'A', which is 65. This variable will be used to print the characters in the pattern.
  5. The first for loop is used to control the number of rows in the pattern. It starts with i initialized to 65 (ASCII value of 'A') and continues as long as i is less than or equal to 69 (ASCII value of 'E').
  6. Inside the first loop, there is a nested for loop that controls the number of columns in each row. It starts with j initialized to 69 (ASCII value of 'E') and continues as long as j is greater than or equal to 65 (ASCII value of 'A').
  7. In each iteration of the inner loop, there is an if statement that checks if j is greater than i. If it is true, two spaces are printed using printf(" "). This creates a pattern of spaces in the initial part of each row.
  8. If the condition in the if statement is false (i.e., j is not greater than i), the else block is executed. Here, the current value of k is printed using printf("%2c", k++). The %2c format specifier is used to print a character with a minimum field width of 2, ensuring that each character is aligned properly. After printing, the value of k is incremented using the post-increment operator k++.
  9. After the inner loop completes, a newline character (\n) is printed using printf("\n").This moves the control to the next line, creating a new row in the pattern.
  10. The outer loop continues to iterate until i becomes 70, which is the first value greater than 69.
  11. Once both loops finish execution, the main() function ends, and the program returns 0, indicating successful execution.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

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👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (C Alphabet Pattern 22) please comment here. I will help you immediately.

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