C Alphabet Triangle Pattern (Right-Angled)

Beginner
6 min read
Updated: Sep 2026
3 programs
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What Is This Pattern?

An alphabet right-angled triangle prints a left-aligned staircase of letters: row i runs from A through the i-th letter (A, AB, ABC, …).

Remember
Rule: on row i, print A through the i-th letter

A
AB
ABC
ABCD
ABCDE     ← 5 rows

In C you solve it with two nested for loops over char: the outer loop picks the end letter, the inner loop restarts at A and prints through that end letter, then printf("\n") moves to the next line. Once this clicks, inverted letter triangles and other alphabet shapes become much easier.

How to Solve It

Two ways to emit the same shape — start with nested char loops and printf, then optionally polish with putchar.

MethodIdeaBest for
Nested loops + printfOuter = end letter; inner = A..end via printf("%c", j)Learning, interviews, exams
Nested loops + putcharSame loops; putchar(j) per letterSlightly leaner demos once loops click

Pseudocode

Pseudocode
for end from 'A' to lastLetter:   // lastLetter depends on rows
    for ch from 'A' to end:
        print ch (no newline)
    print newline

Cheat sheet

GoalPattern
Walk each rowfor (i = 'A'; i <= last; i++)
Print A..ifor (j = 'A'; j <= i; j++) printf("%c", j);
End the rowprintf("\n");
Last letter from rowslast = (char)('A' + rows - 1);
putchar styleputchar(j); then putchar('\n');
Invert laterShrink end letter each row → Program 2

Printing Letters vs Starting a New Line

APIEffectUse for
printf("%c", j)Stays on the same lineEach letter
printf("\n")Ends the current lineAfter the inner loop

Live Preview

Change the row count and the alphabet triangle updates instantly — capped at 26 letters (A–Z).

Whole numbers from 1 to 26. Tap a chip or type a value — the preview redraws as you go.

Live result 5 rows · 15 letters
A
AB
ABC
ABCD
ABCDE

Worked Walkthrough — rows = 4

Trace each outer-loop end letter and count how many times the inner loop prints.

End iInner jPrinted rowLetters
'A'A..AA1
'B'A..BAB2
'C'A..CABC3
'D'A..DABCD4

Total letter prints: 1 + 2 + 3 + 4 = 10 = 4×5/2. That triangular sum is why time is O(n²).

C Programs

Three complete programs: fixed end letter, scanf input, and a putchar shortcut. Use View Output to reveal sample results.

Example 1 — Fixed through 'E'

Hard-coded end letter — ideal for first demos and screenshots (5 rows).

C
#include <stdio.h>

int main(void)
{
    char i, j;

    for (i = 'A'; i <= 'E'; i++)
    {
        for (j = 'A'; j <= i; j++)
        {
            printf("%c", j);
        }
        printf("\n");
    }

    return 0;
}

How It Works

1. Outer loop picks the end letter. i runs from 'A' to 'E' — one row per end letter.

2. Inner loop restarts at A. For each i, j runs from 'A' to i, so the row is A..i.

3. Print letters, then break the line. printf("%c", j) stays on the row; printf("\n") after the inner loop starts the next row.

When i = 'A' you get A; when i = 'B' you get AB; up through ABCDE.

Example 2 — User Input Version

Read the row count at runtime with scanf. Always check its return value in real apps (shown in the tip below).

C
#include <stdio.h>

int main(void)
{
    int rows;
    char i, j, last;

    printf("Enter the number of rows: ");
    scanf("%d", &rows);
    last = (char)('A' + rows - 1);

    for (i = 'A'; i <= last; i++)
    {
        for (j = 'A'; j <= i; j++)
        {
            printf("%c", j);
        }
        printf("\n");
    }

    return 0;
}

How It Works

1. Prompt and read. Ask for a row count, then store it with scanf("%d", &rows).

2. Map rows to an end letter. last = (char)('A' + rows - 1) — for rows = 4, last is 'D'.

3. Same nested-loop core. Only the source of last changes — the print logic matches Example 1.

4. Safer input tip. Unchecked scanf leaves rows uninitialized on bad input. Prefer:

Safer input
if (scanf("%d", &rows) != 1 || rows < 1 || rows > 26)
{
    printf("Enter a whole number from 1 to 26.\n");
    return 1;
}

Example 3 — putchar(j)

Same nested loops — write each letter with putchar instead of printf.

C
#include <stdio.h>

int main(void)
{
    char i, j;

    for (i = 'A'; i <= 'E'; i++)
    {
        for (j = 'A'; j <= i; j++)
        {
            putchar(j);
        }
        putchar('\n');
    }

    return 0;
}

How It Works

1. Same outer and inner bounds. Still walk i from 'A' to 'E' and j from 'A' to i.

2. One character at a time. putchar(j) writes a letter without a format string.

3. End the row. putchar('\n') advances to the next line.

Learn the printf version first (Examples 1–2) so you can explain both bounds in an interview; treat putchar as a polish shortcut afterward.

Edge Cases & Pitfalls

Check these before calling the solution done.

\n inside

Column of letters

If printf("\n") is inside the inner loop, each letter lands on its own line. Print letters without a newline; call printf("\n") only after the inner loop.

No restart

Letters keep advancing

The inner loop must start at 'A' every row. A single advancing counter across rows produces a different pattern.

No newline

One endless line

Omitting the row break glues every letter onto a single line.

rows > 26

Past Z

'A' + rows - 1 leaves A–Z when rows > 26. Clamp or reject in interactive programs.

rows = 1

Single A

Output is just A on one line — a good sanity check.

scanf

Check the return value

If scanf fails, rows may be uninitialized — always test scanf(...) == 1 and prefer 1–26.

Time and Space Complexity

ProgramTimeExtra space
Nested loops + printf (Examples 1–2)O(rows²)O(1)
putchar (Example 3)O(rows²)O(1)

Total letters printed = 1 + 2 + … + n = n(n+1)/2, which is still quadratic in n.

Key Takeaways

  • Rule: row with end letter i prints A through i.
  • Two loops: outer = end letter, inner = A..end with printf("%c", j).
  • Break the row: call printf("\n") only after the inner loop.
  • Complexity: O(n²) time from the triangular letter count; O(1) extra space.

One line: for each end letter i, print A through i with printf("%c", j), then printf("\n").

Frequently Asked Questions

The outer loop picks the last letter on each row. The inner loop always restarts at A and prints up through that last letter, so row 1 is A, row 2 is AB, row 3 is ABC, and so on.
Each row is a fresh sequence from A to the current end letter. If you kept advancing a single char across rows, you would get a different pattern (not this right-angled alphabet triangle).
printf("%c", j) prints a letter and stays on the same line. printf("\n") ends the current line. Letters use %c; the row break uses \n after the inner loop.
Shrink the end letter each row — for example walk the outer loop from the last letter down toward A. See Alphabet Pattern Program 2.
O(n²) where n is the number of rows. Total letter prints equal 1+2+…+n = n(n+1)/2.
Yes. putchar(j) writes one character without a format string. Nested loops with putchar are a common, slightly leaner style; keep printf if your course examples use it.
Check scanf's return value: if (scanf("%d", &rows) != 1) handle bad input. Unchecked scanf leaves rows uninitialized on failure. Clamp to 26 for A–Z demos.
Char math can produce characters beyond Z. Clamp to 26 for A–Z demos, or define a clear wrap/error policy.

Did you know?

Row i prints letters from A through the i-th letter (A, AB, ABC, …). Total letters for n rows is the triangular number n(n+1)/2 — the same count that makes this pattern O(n²).

Next: Inverted Alphabet Triangle

Flip the outer loop and shrink the end letter each row.

Program 2 tutorial →

About the author

Mari Selvan M P
Mari Selvan M P 🔗

Developer, cloud engineer, and technical writer

  • Experience 12 years building web and cloud systems
  • Focus Full Stack Development, AWS, and Developer Education

I write practical tutorials so students and working developers can learn by doing—from databases and APIs to deployment on AWS.

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