Java Star Pattern 2

Posted in Java Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 312 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

Java Star Pattern 2

Here`s a program that prints the above star pattern using Java Programming:

Demo.java

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public class Demo
{
 public static void main(String[] args)
 {
  int i, j;
  for(i=5; i>=1; i--)
  {
   for(j=1; j<=i; j++)
    System.out.print("*");
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

*****
****
***
**
*

🧠 How the Program Works

Let's break down the logic behind the code:

Class Declaration: The program starts with the declaration of a class named Demo.
main Method: Inside the Demo class, there is a public static void main(String[] args) method, which is the entry point of the program. This is where the program execution begins.
Variable Declaration: Inside the main method, two integer variables i and j are declared but not initialized. These variables will be used in the loops to control the number of asterisks printed and the number of rows.
Outer Loop (for loop): The outer loop is used to control the number of rows in the pattern. It starts with i equal to 5 and iterates as long as i is greater than or equal to 1. In each iteration, i is decremented by 1.
- for(i=5; i>=1; i--): This loop initializes i to 5, and it continues as long as i is greater than or equal to 1. In each iteration, i is decremented by 1.
Inner Loop (for loop): Inside the outer loop, there is another loop, which is the inner loop. This loop is responsible for printing the asterisks on each row. It starts with j equal to 1 and iterates as long as j is less than or equal to i. In each iteration, j is incremented by 1.
- for(j=1; j<=i; j++): This loop initializes j to 1 and continues as long as j is less than or equal to i. In each iteration, j is incremented by 1.
Printing Asterisks: Inside the inner loop, the program prints an asterisk (*) using System.out.print("*"). This statement prints an asterisk without moving to the next line.
Newline Character: After the inner loop, there is a System.out.println() statement. This statement prints a newline character, which moves the cursor to the next line, creating a new row in the pattern.
Repeat: The inner loop continues to print asterisks and move to the next line until j is no longer less than or equal to i. At this point, the inner loop terminates.
Repeat Outer Loop: The outer loop then continues to the next iteration with a decremented value of i. This process continues until i becomes less than 1, at which point the outer loop terminates.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the star pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!