Java Alphabet Pattern 34

Posted in Java Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 118 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

Java Alphabet Pattern 34

Here`s a program that prints the above alphabet pattern using Java Programming:

Demo.java

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public class Demo
{
 public static void main(String[] args)
 {
  int i, j, k;
  for(i=65; i<=69; i++) 
  {
   for(j=69; j>=65; j--)
   {
    if(i == j)
     System.out.format("%c", j);
    else
     System.out.print(" ");
   }
   for(k=66; k<=69; k++)
   {
    if(i == k)
     System.out.format("%c", k);
    else
     System.out.print(" ");
   }
   System.out.println();
  }
  for(i=68; i>=65; i--)
  {
   for(j=69; j>=65; j--)
   {
    if(i == j)
     System.out.format("%c", j);
    else
     System.out.print(" ");
   } 
   for(k=66; k<=69; k++)
   {
    if(i == k)
     System.out.format("%c", k);
    else
     System.out.print(" ");
   }
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

    A
   B B
  C   C
 D     D
E       E
 D     D
  C   C
   B B
    A

🧠 How the Program Works

Let's break down the logic behind the code:

public class Demo: This line defines a public class named Demo.
public static void main(String[] args): This is the main method of the program, where execution begins when you run the program.
Inside the main method, you'll find several nested loops used to print the 'E' pattern:
1. for(i=65; i<=69; i++): This is an outer loop that iterates from the ASCII value 65 (which corresponds to the letter 'A') to 69 (which corresponds to the letter 'E'). It controls the rows of the pattern.
2. for(j=69; j>=65; j--): This is the first inner loop, which initializes j to 69 (letter 'E') and decrements it down to 65 (letter 'A'). It controls the left side of the 'E' pattern.
3. Inside the first inner loop, there's an if statement that checks if i (the current row) is equal to j (the current column). If they are equal, it prints the current character (e.g., 'A', 'B', 'C', 'D', or 'E') using System.out.format("%c", j), otherwise, it prints a space using System.out.print(" ").
4. After the first inner loop, there's a second inner loop with k to control the right side of the 'E' pattern. This loop iterates from 66 (letter 'B') to 69 (letter 'E'). It has a similar if statement to print characters or spaces.
5. Finally, after the two inner loops, there's System.out.println(); to move to the next line for the next row of the pattern.
After the first set of loops (for 'A' to 'E'), there is a second set of loops to print the mirrored 'E' pattern:
1. for(i=68; i>=65; i--): This loop starts from the ASCII value 68 (letter 'D') and decrements i down to 65 (letter 'A').
2. Inside this loop, there are two inner loops that print the left and right sides of the 'E' pattern, similar to the first set of loops.
3. Again, System.out.println(); is used to move to the next line after each row.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!