Front-end Tutorials

Front-end Tutorials

HTMLCSSSassJavaScriptReactJS
CMS Tutorials

CMS Tutorials

WordPress
Tutorials expand

Java Alphabet Pattern 31

Posted in Java Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 179 - Views
⏳ 4 mins
💬 1 Comment
Java Alphabet Pattern 31

Photo Credit to CodeToFun

Java Alphabet Pattern 31

Here`s a program that prints the above alphabet pattern using Java Programming:

Demo.java
Copied
Copy To Clipboard
public class Demo
{
 public static void main(String[] args)
 {
  int i, j, k;
  for(i=65; i<=69; i++)
  {
   for(j=65; j<=69; j++)
   {
    if(i == j)
     System.out.format("%c", j);
    else
     System.out.print(" ");
   }
   for(k=68; k>=65; k--)
   {
    if(i == k)
     System.out.format("%c", k);
    else
     System.out.print(" ");
   }
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
A       A
 B     B
  C   C
   D D
    E

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program defines a public class named Demo.
  2. Inside the class, there's a public static void main(String[] args) method, which is the entry point of the program.
  3. Inside the main method, three integer variables i, j, and k are declared.
  4. The program enters a nested loop structure with two for loops. The outer loop runs from i = 65 to i <= 69, and the inner loop runs from j = 65 to j <= 69.
  5. Inside the innermost loop, there's an if statement that checks if i is equal to j. If i is equal to j, it prints the character represented by the ASCII value of j using System.out.format("%c", j);. Otherwise, it prints a space using System.out.print(" ");.
  6. After the inner loop finishes executing, there is another nested loop structure. This time, it's for variable k, which runs from k = 68 down to k >= 65.
  7. Inside the innermost loop for k, there's another if statement that checks if i is equal to k. If i is equal to k, it prints the character represented by the ASCII value of k using System.out.format("%c", k);. Otherwise, it prints a space using System.out.print(" ");.
  8. After both inner loops complete, a newline character is printed using System.out.println() to move to the next row of the pattern.
  9. The outer loop repeats, and the process continues until i is no longer less than or equal to 69.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

👨‍💻 Join our Community:

To get interesting news and instant updates on Front-End, Back-End, CMS and other Frameworks. Please Join the Telegram Channel:

Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

Buy me a coffee to make codetofun.com free for everyone.

Buy me a Coffee

Share Your Findings to All

Subscribe
Notify of
guest
1 Comment
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (Java Alphabet Pattern 31), please comment here. I will help you immediately.

We make use of cookies to improve our user experience. By using this website, you agree with our Cookies Policy
AgreeCookie Policy