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C++ Star Pattern 7

Posted in C++ Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 116 - Views
⏳ 4 mins
💬 1 Comment
C++ Star Pattern 7

Photo Credit to CodeToFun

C++ Star Pattern 7

Here`s a program that prints the above star pattern using C++ Programming:

example.cpp
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#include <iostream>
using namespace std;

int main() {
  int i, j, k;
  for (i = 1; i <= 5; i++) {
    for (j = 5; j >= 1; j--) {
      if (i == j)
        cout << "*";
      else
        cout << " ";
    }
    for (k = 2; k <= 5; k++) {
      if (i == k)
        cout << "*";
      else
        cout << " ";
    }
    cout << "\n";
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
     *
    * *
   *   *
  *     *
 *       *

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program includes the necessary header file, <iostream>, which allows us to use input and output stream objects such as cin and cout.
  2. The line using namespace std; tells the compiler that we want to use the standard namespace. This simplifies the code by allowing us to write cout instead of std::cout, for example.
  3. The main() function is the entry point of the program and where the execution begins.
  4. Inside the main() function, three integer variables i, j, and k are declared. These variables will be used as loop counters and control the flow of the program.
  5. The outer for loop initializes i to 1 and continues as long as i is less than or equal to 5. It increments i by 1 after each iteration.
  6. Inside the outer for loop, there are two nested for loops.
  7. The first nested for loop initializes j to 5 and continues as long as j is greater than or equal to 1. It decrements j by 1 after each iteration.
  8. Inside this loop, there is an if statement that checks if i is equal to j. If the condition is true, it means the values of i and j are the same, so an asterisk * is printed using cout << "*". Otherwise, a space character is printed.
  9. After the first nested for loop, there is a second nested for loop.
  10. The second nested for loop initializes k to 2 and continues as long as k is less than or equal to 5. It increments k by 1 after each iteration.
  11. Inside this loop, there is another if statement that checks if i is equal to k. If the condition is true, an asterisk * is printed using cout << "*". Otherwise, a space character is printed.
  12. After the second nested for loop, a newline character (\n) is printed using cout << "\n". This moves the cursor to the next line, creating a new line for the next iteration of the outer for loop.
  13. The program continues with the next iteration of the outer for loop until i becomes greater than 5.
  14. Finally, the return 0; statement indicates that the program has finished executing and returns the value 0 to the operating system, indicating successful termination.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the star pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

Buy me a coffee to make codetofun.com free for everyone.

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Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (C++ Star Pattern 7) please comment here. I will help you immediately.

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