C++ Number Pattern 45

Posted in C++ Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 95 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

C++ Number Pattern 45

Here`s a program that prints the above number pattern using C++ Programming:

example.cpp

Copied

#include <iostream>
using namespace std;

int main() {
  int i, j;
  for (i = 1; i <= 4; i++) {
    for (j = 1; j <= 9; j++) {
      if (i == j || j == 5 || i == 10 - j)
        cout << "*";
      else
        cout << "0";
    }
    cout << "\n";
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

*000*000*
0*00*00*0
00*0*0*00
000***000

🧠 How the Program Works

Let's break down the logic behind the code:

The program starts with the inclusion of the <iostream> library, which provides input/output stream functionality.
The using namespace std; line allows us to use the standard namespace without explicitly specifying it for each identifier.
The main() function is the entry point of the program.
Two integer variables, i and j, are declared to be used as loop counters.
The outer for loop initializes i to 1 and repeats until i is no longer less than or equal to 4. It increments i by 1 after each iteration.
Inside the outer loop, there is another for loop that initializes j to 1 and repeats until j is no longer less than or equal to 9. It increments j by 1 after each iteration.
Inside the nested loop, there is an if statement that checks three conditions:
- If i is equal to j, it means that the current position is on the main diagonal of the pattern. In this case, a '*' character is printed.
- If j is equal to 5, it means that the current position is on the middle column of the pattern. In this case, a '*' character is printed.
- If i is equal to 10 minus j, it means that the current position is on the opposite diagonal of the pattern. In this case, a '*' character is printed.
If none of the conditions in the if statement are met, the else block is executed, and a '0' character is printed.
After each character is printed in the nested loop, the control goes back to the outer loop, and a newline character ("\n") is printed to move to the next line.
The program continues this pattern until the outer loop condition is no longer satisfied.
Finally, the main() function returns 0 to indicate successful program execution, and the program terminates.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!