C Alphabet Pattern 8

Posted in C Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 105 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

C Alphabet Pattern 8

Here`s a program that prints the above alphabet pattern using C Programming:

example.c

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#include <stdio.h>
int main()
{
 int i, j;
 for(i=65; i<=69; i++)
 {
  for(j=69; j>=i; j--)
   printf("%c", j);
  printf("\n");
 }
 return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

EDCBA
EDCB
EDC
ED
E

🧠 How the Program Works

Let's break down the logic behind the code:

The program starts by including the stdio.h header file, which provides input/output functions such as printf.
Inside the main function, two variables i and j are declared to be used as loop counters.
The outer for loop runs from i = 65 to i <= 69. The ASCII value of 'A' is 65, and 'E' is 69, so the loop iterates five times, representing the five rows of the pattern.
Within each iteration of the outer loop, the inner for loop runs from j = 69 to j >= i. The ASCII value of 'E' is 69, and it decrements by one in each iteration, printing the letters in a decreasing sequence.
The %c format specifier is used with printf to print the characters based on their ASCII values.
After printing the required number of letters for the current row, a newline character \n is printed to move to the next line.
This process repeats until all rows are printed.
Finally, the main function returns 0 to indicate successful program execution.

Each row contains a decreasing sequence of letters, starting from 'E' and ending with 'A'. The number of letters in each row corresponds to the row number, with the first row having five letters and the last row having only one letter.