Java Program to Check Pronic Number

Posted in Java Tutorial

Updated on Oct 30, 2024

By Mari Selvan

👁️ 65 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

🙋 Introduction

In the realm of programming, mathematical patterns and properties often become interesting challenges. One such intriguing concept is the "Pronic Number."

A pronic number, also known as a rectangular number, oblong number, or heteromecic number, is the product of two consecutive integers.

In this tutorial, we will delve into a Java program designed to check whether a given number is a pronic number or not.

📄 Example

Now, let's delve into the Java code that checks whether a given number is a pronic number or not.

PronicNumberChecker.java

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public class PronicNumberChecker {

  // Function to check if a number is a pronic number
  static boolean isPronic(int num) {
    int sqrtNum = (int) Math.sqrt(num);

    return (sqrtNum * (sqrtNum + 1) == num);
  }

  // Driver program
  public static void main(String[] args) {
    // Replace this value with your desired number
    int number = 12;

    // Check if the number is a pronic number
    if (isPronic(number)) {
      System.out.println(number + " is a pronic number.");
    } else {
      System.out.println(number + " is not a pronic number.");
    }
  }
}

💻 Testing the Program

To test the program with different numbers, simply replace the value of number in the main method.

Output

12 is a pronic number.

Compile and run the program to check if the given number is a pronic number.

🧠 How the Program Works

The program defines a class PronicNumberChecker containing a static method isPronic that takes a number as input and returns true if the number is a pronic number and false otherwise.
Inside the method, it calculates the square root of the input number.
It checks whether the product of the square root and the square root incremented by 1 equals the input number. If yes, the number is a pronic number.
The driver program tests the function with a sample number and prints the result.

📏 Between the Given Range

Let's take a look at the java code that checks for pronic numbers in the range from 1 to 20.

PronicNumbers.java

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public class PronicNumbers {

  // Function to check if a number is Pronic
  static boolean isPronic(int num) {
    int sqrt = (int) Math.sqrt(num);
    return (sqrt * (sqrt + 1) == num);
  }

  // Driver program
  public static void main(String[] args) {
    System.out.print("Pronic Numbers in the range 1 to 20:\n");

    // Check and display Pronic Numbers in the range 1 to 20
    for (int i = 1; i <= 20; i++) {
      if (isPronic(i)) {
        System.out.print(i + " ");
      }
    }
  }
}

💻 Testing the Program

Output

Pronic Numbers in the range 1 to 20:
2 6 12 20

Compile and run the program to see the Pronic Numbers in the specified range.

🧠 How the Program Works

The program defines a class PronicNumbers containing a static method isPronic to check if a given number is Pronic.
Inside the method, it calculates the square root of the number and checks if it satisfies the Pronic condition (n×(n+1)==num).
The main function iterates through the range from 1 to 20 and prints the Pronic Numbers.

🧐 Understanding the Concept of Pronic Numbers

Before delving into the code, let's take a moment to understand the concept of pronic numbers.

A pronic number is a product of two consecutive integers, and it has applications in various mathematical and geometric contexts.

A pronic number, denoted by P_n, is a number of the form P_n=n × (n+1) where n is a non-negative integer. The sequence of pronic numbers starts as 0, 2, 6, 12, 20, and so on.

For example, let's take n = 3. The corresponding pronic number would be P₃ = 3x(3+1) = 12.