Shape Rule
j % 2 alternates 0 and 1
Row 1 prints 1, row 2 prints 01, row 3 prints 101, and so on as width grows.

The alternating binary number triangle combines nested loops with the modulo operator to print 0 and 1 in an alternating sequence. This tutorial covers the shape rule, loop structure, a live preview, algorithm steps, worked Python examples, edge cases, and complexity.
j % 2 alternates 0 and 1
Row 1 prints 1, row 2 prints 01, row 3 prints 101, and so on as width grows.
Rows
for i in range(1, rows + 1) makes each new row one digit longer than the previous.
i..1 descending
for j in range(i, 0, -1) prints j % 2 while counting down, creating the alternating binary row.
Same line / next line
Binary digits use print(j % 2, end=""); end each row with print().
1–20 rows
Pick a row count and draw the alternating binary triangle instantly in the browser.
Complexity
Total digit prints still = n(n+1)/2; extra memory stays O(1).
An alternating binary number triangle grows each row by one digit while alternating between 0 and 1 using the modulo operator. With rows = 5, the output is 1, 01, 101, 0101, 10101.
In Python you solve it with an ascending outer loop and a descending inner loop: for j in range(i, 0, -1) prints j % 2, then print() ends each row.
It is a fun way to practice parity and nested loops before more complex logic-heavy patterns.
j % 2 yields 0 for even j, 1 for odd j.
j = i down to 1 sets digit order on each row.
print(j % 2, end="") in the inner loop; print() after.
Follow Program 14; continue to Program 16 (ascending inner loop).
In short: for each row i from 1 to rows, print j % 2 for j from i down to 1, then call print().
Given a positive integer rows, print an alternating binary number triangle: row i has i digits from j % 2 as j counts down from i to 1.
# rows = 5 (conceptual shape)
# 1
# 01
# 101
# 0101
# 10101
for i in range(1, rows + 1):
for j in range(i, 0, -1):
print(j % 2, end="") # binary digit from parity
print() # next row | Item | Type | Description |
|---|---|---|
rows | int | Number of triangle lines to print (typically ≥ 1). |
| Printed output | text | Each row has i alternating binary digits from j % 2. |
for i from 1 to rows:
for j from i down to 1:
print j % 2 (no newline)
print newline | Approach | Idea | Best for |
|---|---|---|
Descending inner + j % 2 | 1, 01, 101, … | Learning and interviews |
Flip with 1 - (j % 2) | Start rows with 0 instead of 1 | Parity inversion variant |
| Goal | Pattern |
|---|---|
| Walk each row | for i in range(1, rows + 1): |
| Print binary digit | for j in range(i, 0, -1): print(j % 2, end="") |
| End the row | print() |
| Flip parity | print(1 - (j % 2), end="") |
| Program 16 variant | for j in range(1, i + 1): print(j % 2, end="") (ascending inner) |
| Row + column parity | print((i + j) % 2, end="") |
Same binary triangle family — different ways to emit 0 and 1.
parityEven j → 0, odd j → 1
flippedInverts every digit — row 1 starts with 0
desc innerThis page — produces 1, 01, 101, …
% 2 firstMaster j % 2 before row+column parity
Reach for this pattern when teaching the modulo operator inside nested loops.
Most Python pattern series start here before pyramids and diamonds.
Outer/inner bound practice with an immediate visual check.
Combine loops with input() for a flexible row count.
Compare Program 14 (odd-length rows) and Program 16 (ascending inner loop) next.
This is a console teaching pattern — not how you build modern app screens.
Key benefit: one small program that locks in nested loops, output sequencing, and O(n²) thinking.
Choose a row count between 1 and 20 and draw the alternating binary triangle in the browser.
Three complete Python programs — fixed rows, a flip variant, and a user-input version. Click View Output to reveal sample console results.
Print five rows of the alternating binary triangle with j % 2.
rows = 5Hard-coded height — ideal for first demos and screenshots.
rows = 5
for i in range(1, rows + 1):
for j in range(i, 0, -1):
print(j % 2, end="")
print() When i = 1, the inner loop prints 1 % 2 = 1. When i = 3, it prints 3%2=1, 2%2=0, 1%2=1 as 101, and so on as row width grows. print() after the inner loop starts the next row.
Invert parity so the first row starts with 0 instead of 1.
1 - (j % 2)Start each row with 0 instead of 1 by inverting the parity output.
rows = 5
for i in range(1, rows + 1):
for j in range(i, 0, -1):
print(1 - (j % 2), end="")
print() 1 - (j % 2) flips every digit: where j % 2 was 1 it prints 0, and vice versa. Row 1 becomes 0 instead of 1.
Read the row count at runtime and scale the binary triangle.
Read rows with input() and int() (wrap in try/except ValueError in real apps) and apply the same j % 2 logic.
rows = int(input("Enter the number of rows: "))
for i in range(1, rows + 1):
for j in range(i, 0, -1):
print(j % 2, end="")
print() Same nested-loop core as Example 1; only the source of rows changes. Non-numeric input raises ValueError with bare int(input()) — use try/except for safer labs.
print is built in; use input() when reading input. Set rows (fixed or from input).
for i in range(1, rows + 1): makes each row one digit longer than the previous.
for j in range(i, 0, -1): prints j % 2 with print(j % 2, end="") to alternate 0 and 1.
print() ends the row so the next outer iteration starts fresh.
Total digit prints: 1+2+…+n = n(n+1)/2 — O(n²) time, O(1) extra memory.
rows = 4Trace each outer-loop value of i and note the j % 2 values printed on each row.
i | Inner j order | j % 2 values | Printed row |
|---|---|---|---|
1 | 1 | 1 | 1 |
2 | 2, 1 | 0, 1 | 01 |
3 | 3, 2, 1 | 1, 0, 1 | 101 |
4 | 4, 3, 2, 1 | 0, 1, 0, 1 | 0101 |
Total digit prints: 1 + 2 + 3 + 4 = 10 = 4×5/2.
Where this tiny pattern (and its loop structure) shows up beyond the homework prompt.
Clearest visual proof that outer and inner bounds interact.
Example: change j <= i and watch the shape change.
Foundation for inverted, pyramid, diamond, and hollow variants.
Example: use (i + j) % 2 for row+column parity grids.
Practice print(..., end="") vs row newline without complex math.
Example: put print() inside the inner loop by mistake.
Swap digits for letters, stars, or spaced output once the loop works.
Example: use print(j % 2, end=" ") for spaced digits on each row.
Triangular totals make O(n²) concrete for beginners.
Example: count printed digits for n = 10 still → 55.
Pair the pattern with try/except ValueError around int(input()) and positive-row checks.
Example: reject rows <= 0 and re-prompt.
Pro Tip: when an interviewer asks for patterns, explain the outer/inner roles first — then write the loops. The story matters as much as the code.
Why this pattern earns a permanent spot in beginner Python courses.
Wrong bounds show up immediately as a broken staircase.
Only loops and console output — no arrays or math libraries.
Invert, center, hollow, or change the fill character with small edits.
Streaming output needs no storage beyond loop counters.
Pro Tip: learn j % 2 first; compare with 1 - (j % 2) to flip every digit on each row.
Small habits that keep number-pattern code clean.
Use rows (or n) and keep i/j for row/column — or rename to row/col.
try/except ValueErrorWrap int(input()) in try/except ValueError so bad input does not leave rows unset.
Only call print() after the inner loop finishes the row.
Write the j values and their modulo before coding — catches direction mistakes early.
Trace rows = 5 on paper before coding larger demos.
Pro Tip: if the output is a vertical list of single digits per line, you almost certainly put print() inside the inner loop.
Mistakes that commonly break alternating binary number patterns.
Each digit lands on its own line — you get a column, not a triangle.
→ Use print(j % 2, end="") for binary digits; print() only after the inner loop.
Counting j up instead of down changes row ordering (see Program 16).
→ For this shape, keep for j in range(i, 0, -1).
Omitting print() glues every digit onto one endless line.
→ Always end the row after the inner loop.
Letters or empty input raise ValueError with bare int(input()).
→ Catch ValueError and re-prompt on failure.
Switching to a 0-based outer loop without adjusting the stop value can drop the last row or print an empty first row.
→ Prefer range(1, rows + 1) with range(i, 0, -1) for the digits.
Check these inputs before calling the solution done.
Output is just 1 on one line.
Outer loop never runs — print nothing or show a message.
rows < 0Treat as invalid; re-prompt instead of silent empty output.
Output grows as n²/2 characters — fine for labs, noisy for huge n.
int(input()) raises ValueError — validate with try/except first.
print(j, end="") prints 1,2,3… — use print(j % 2, end="") for binary output.
Try these variations to lock in the pattern.
range(..., -2) for odd widths onlyrange(1, i + 1) instead of down1 - (j % 2) so row 1 starts with 0print(j % 2, end=" ") between digitsn rows.print(j % 2, end="") stays on the line; print() advances — mix them carefully.rows > 0 for interactive programs; rows = 1 should print a single 1.Quick Takeaway: outer loop grows row length, inner loop prints j % 2 descending, then break the line.
| Program | Time | Extra space |
|---|---|---|
| Nested loops (Examples 1–2) | O(rows²) | O(1) |
| User input (Example 3) | O(rows²) | O(1) |
The alternating binary number triangle is a compact lesson in modulo inside nested loops. Master the j % 2 version, then try the flip variant with 1 - (j % 2).
Practice the three examples above, then continue to Program 16 for the ascending-inner-loop binary triangle.
Use j % 2 for alternating 0/1 — keep print for digits and print() for the break, and validate row counts when reading input.
j % 2 before coding descending inner loopprint(j % 2, end="") for digits and print() after each rowrows ≥ 1 for interactive programsint(input()) in try/except ValueError before using rowsprint() inside the inner digit loopj directly instead of j % 2j up when you meant this page’s descending inner looprows = 1 edge casePrint the pattern the beginner-friendly way.
j % 2 alternates 0 and 1
DefinitionGrows row length each line
Codej % 2 picks digit
LogicEnds each row
I/OO(n²) time
AnalysisEach row prints alternating 0 and 1 using j % 2. The inner loop counts down with range(i, 0, -1), so row length grows each line — still O(n²) total prints.
Move on to the column-wise alternating binary pattern in the Python number-pattern series.
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