Shape Rule
digit i repeats exactly i times
Row rows prints rows repeated rows times, then each next row repeats its digit fewer times down to a single 1.

The inverted repeating number triangle widens first then shrinks: digit i repeats exactly i times — nested loops, print(..., end="") vs print(), and a clear visual result. This tutorial covers the shape rule, loop structure, a live preview, algorithm steps, worked Python examples, edge cases, and complexity.
digit i repeats exactly i times
Row rows prints rows repeated rows times, then each next row repeats its digit fewer times down to a single 1.
Rows
for i in range(rows, 0, -1): walks each line from the longest down to one digit.
Digits
for j in range(1, i + 1): prints digit i exactly i times on that row.
Same line / next line
Repeated digits use print(i, end=""); end each row with print().
1–20 rows
Pick a row count and draw the inverted repeating number triangle instantly in the browser.
Complexity
Total digit prints still = n(n+1)/2; extra memory stays O(1).
An inverted repeating number triangle pattern starts with the widest row and loses one repeat each line as the digit decreases. Each row prints the same digit multiple times; the repeat count shrinks while the digit value shrinks.
In Python you usually solve it with two nested for loops: the outer loop picks the digit, the inner loop repeats it with print(i, end=""), then print() moves to the next line.
It pairs naturally with Program 10 in Python courses. Once nested loops and print(..., end="")/print() click, pyramids, diamonds, and hollow shapes become much easier.
On row i, print digit i exactly i times.
Outer picks the digit; inner controls how many times it repeats.
print(i, end="") in the inner loop; print() after.
Gateway to Program 10 (5, 44, 333, …) and Program 12.
In short: for each row i from rows down to 1, repeat print(i, end="") exactly i times, then call print().
Given a positive integer rows, print an inverted repeating number triangle: row i repeats digit i exactly i times, with the outer loop counting from rows down to 1.
# First 5 rows (conceptual shape)
# 55555
# 4444
# 333
# 22
# 1
for i in range(rows, 0, -1):
for j in range(1, i + 1):
print(i, end="") # digit i, repeated i times
print() # next row | Item | Type | Description |
|---|---|---|
rows | int | Number of triangle lines to print (typically ≥ 1). |
| Printed output | text | Each row repeats one digit; the top row has rows copies of rows, the bottom row has a single 1. |
for i from rows down to 1:
repeat i times:
print i (no newline)
print newline | Approach | Idea | Best for |
|---|---|---|
| Nested loops | Outer digit + inner repeats | Learning and interviews |
str(i) * i in inner loop | Print a full repeated row with str(i) * | Leaner Python style once loops are understood |
| Goal | Pattern |
|---|---|
| Walk each row | for i in range(rows, 0, -1): |
Repeat digit i | for j in range(1, i + 1): print(i, end="") |
| End the row | print() |
| One-line row shortcut | str(i) * i repeated per row |
| Program 10 variant | for j in range(rows, i - 1, -1): print(i, end="") (descending repeats) |
Same triangle — different ways to emit characters.
same linePrints a digit without moving to the next line
new lineEnds the current row after all digits are printed
one digitWrites digit i when i is 1..9 — no format string
loops firstMaster nested loops before the str(i) * shortcut
Reach for this triangle when teaching or testing nested-loop basics.
Most Python pattern series start here before pyramids and diamonds.
Outer/inner bound practice with an immediate visual check.
Combine loops with input() for a flexible row count.
Compare Program 10 (5, 44, 333, …) and Program 12 next.
This is a console teaching pattern — not how you build modern app screens.
Key benefit: one small program that locks in nested loops, output sequencing, and O(n²) thinking.
Choose a row count between 1 and 20 and draw the inverted repeating number triangle in the browser.
Three complete Python programs — fixed row count, input(), and a str(i) * shortcut. Click View Output to reveal sample console results.
Print five rows of the inverted repeating number triangle with nested loops.
rows = 5Hard-coded height — outer picks digit, inner repeats it i times.
rows = 5
for i in range(rows, 0, -1):
for j in range(1, i + 1):
print(i, end="")
print() When i = 5, the inner loop runs five times and prints 55555. When i = 4, it prints 4444, and so on until i = 1 prints 1. print() after the inner loop starts the next row.
Let the user choose the height at runtime.
Read the row count with input() and int() (wrap in try/except ValueError in real apps).
rows = int(input("Enter the number of rows: "))
for i in range(rows, 0, -1):
for j in range(1, i + 1):
print(i, end="")
print() Same nested-loop core as Example 1; only the source of rows changes. Non-numeric input raises ValueError with bare int(input()) — use try/except for safer labs.
Same shape without an explicit inner repeat loop.
str(i) * iBuild each row with str(i) * i, then print it.
rows = 5
for i in range(rows, 0, -1):
print(str(i) * i) str(i) * i creates a string of repeated digit i. Great once you understand the nested-loop idea; keep the two-loop version for exams that ask you to show both bounds.
print() is built in; use input() when reading input. Set rows (fixed or from input).
for i in range(rows, 0, -1): picks the digit; the inner loop prints it i times.
for j in range(1, i + 1): repeats digit i exactly i times with print(i, end="").
print() ends the row so the next outer iteration starts fresh.
Total digit prints: 1+2+…+n = n(n+1)/2 — O(n²) time, O(1) extra memory.
rows = 4Trace each outer-loop value of i and count how many times the inner loop prints digit i.
i | Inner j range | Repeats | Printed row |
|---|---|---|---|
4 | 1..4 | 4 | 4444 |
3 | 1..3 | 3 | 333 |
2 | 1..2 | 2 | 22 |
1 | 1..1 | 1 | 1 |
Total digit prints: 1 + 2 + 3 + 4 = 10 = 4×5/2.
Where this tiny pattern (and its loop structure) shows up beyond the homework prompt.
Clearest visual proof that outer and inner bounds interact.
Example: change j <= i and watch the shape change.
Foundation for inverted, pyramid, diamond, and hollow variants.
Example: Program 10 uses for j in range(rows, i - 1, -1) so repeats grow as the digit shrinks.
Practice print vs row newline without complex math.
Example: put print() inside the inner loop by mistake.
Swap digits for letters, stars, or spaced output once the loop works.
Example: print i + " " for spaced repeated digits on each row.
Triangular totals make O(n²) concrete for beginners.
Example: count printed digits for n = 10 still → 55.
Pair the pattern with input() and positive-row checks.
Example: reject rows <= 0 and re-prompt.
Pro Tip: when an interviewer asks for patterns, explain the outer/inner roles first — then write the loops. The story matters as much as the code.
Why this pattern earns a permanent spot in beginner C courses.
Wrong bounds show up immediately as a broken staircase.
Only loops and console output — no arrays or math libraries.
Invert, center, hollow, or change the fill character with small edits.
Streaming output needs no storage beyond loop counters.
Pro Tip: learn the nested-loop version first; treat str(i) * i as a polish shortcut afterward.
Small habits that keep number-pattern code clean.
Use rows (or n) and keep i/j for row/column — or rename to row/col.
try/except ValueErrorAvoid crashes when the user types letters instead of a number.
Only call print() after the inner loop finishes the row.
for j in range(1, i + 1): with print(i, end="") repeats digit i exactly i times.
Trace rows = 3 on paper before coding larger demos.
Pro Tip: if the output is a vertical list of single digits per line, you almost certainly put print() inside the inner loop.
Mistakes that commonly break inverted repeating number patterns.
Each repeated digit lands on its own line — you get a column, not a triangle.
→ Use print(i, end="") for repeats; print() only after the inner loop.
Using for j in range(rows, i - 1, -1) builds Program 10 (5, 44, 333…). Using range(1, rows + 1) on every row prints a rectangle.
→ For this shape, keep for j in range(1, i + 1) so digit i repeats exactly i times.
Omitting print() glues every repeat onto one endless line.
→ Always end the row after the inner loop.
Letters or empty input raise ValueError with bare int(input()).
→ Catch ValueError and re-prompt on failure.
Switching to i = 0 without adjusting the digit and repeat count prints an empty first row or wrong counts.
→ Prefer 1-based range(rows, 0, -1) with range(1, i + 1), or carefully map both values if you go 0-based.
Check these inputs before calling the solution done.
Output is just one copy of rows on one line.
Outer loop never runs — print nothing or show a message.
rows < 0Treat as invalid; re-prompt instead of silent empty output.
Output grows as n²/2 characters — fine for labs, noisy for huge n.
int(input()) raises ValueError — validate first.
Use j <= i so row i repeats exactly i times.
Try these variations to lock in the pattern.
for i in range(rows, 0, -1): as outer looprows >= 1 after int(input())print(i, end="") between repeated digitsn(n+1)/2 — hence O(n²) time.print(..., end="") stays on the line; print() advances — mix them carefully.rows > 0 for interactive programs; rows = 1 should print rows copies of the top digit.Quick Takeaway: outer loop picks the row, inner loop repeats digit i, then break the line — that is the whole pattern.
| Program | Time | Extra space |
|---|---|---|
| Nested loops (Examples 1–2) | O(rows²) | O(1) |
str(i) * i (Example 3) | O(rows²) | O(rows) per row string (temporary) |
The inverted repeating number triangle pattern is a small nested-loop exercise with lasting payoff: row/column thinking, print(..., end="") vs print(), and O(n²) intuition. Master the classic two-loop version, then optionally shorten rows with str(i) * i.
Practice the three examples above, then continue to Program 12 for the next pattern in the series.
Row i repeats digit i — keep print(i, end="") for each copy and print() for the break, and validate row counts when reading input.
print(i, end="") for repeats and print() after each rowrows ≥ 1 for interactive programsint(input()) in try/except ValueError before using rowsprint() inside the inner repeat loopfor j in range(rows, i - 1, -1) when you meant Program 10 insteadrows = 1 edge casePrint the triangle the beginner-friendly way.
Row i repeats digit i
Picks the digit each row
CodeRepeats digit with print(i, end="")
Ends each row
I/OO(n²) time
AnalysisRow digit i repeats exactly i times. The outer loop counts down from rows, so the first row is widest (rows copies of rows) and each line shortens — still O(n²) total prints.
Next up — ascending repeating shrinking pattern in the series.
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