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Python Alphabet Pattern 29

Posted in Python Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 101 - Views
⏳ 4 mins
💬 1 Comment
Python Alphabet Pattern 29

Photo Credit to CodeToFun

Python Alphabet Pattern 29

Here`s a program that prints the above alphabet pattern using Python Programming:

example.py
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k = 70
for i in range(69, 64, -1):
    for j in range(k-1, 65, -1):
        if(j > i):
           a = chr(j)
        else:
           a = chr(i)
        print(a, end=" ")

    for j in range(65, k):
        if(j > i):
            b = chr(j)
        else:
            b = chr(i)
        print(b, end=" ")
    print()

for i in range(66, k):
    for j in range(k-1, 65, -1):
        if(j > i):
            a = chr(j)
        else:
            a = chr(i)
        print(a, end=" ")
    for j in range(65, k):
        if(j > i):
            b = chr(j)
        else:
            b = chr(i)
        print(b, end=" ")
    print()

💻 Testing the Program

When you run the above program, it will print the following output:

Output
E E E E E E E E E
E D D D D D D D E
E D C C C C C D E
E D C B B B C D E
E D C B A B C D E
E D C B B B C D E
E D C C C C C D E
E D D D D D D D E
E E E E E E E E E

🧠 How the Program Works

Let's break down the logic behind the code:

  1. k = 70: This line initializes a variable k with the value 70.
  2. The program enters the first outer loop using for i in range(69, 64, -1):.
    • This loop iterates from 69 to 64 (inclusive) in reverse order, with i taking on each value in that range.
  3. Inside the first outer loop, there are two nested loops.
    • The first inner loop, for j in range(k-1, 65, -1):, iterates from k-1 down to 65 (inclusive) in reverse order, with j taking on each value in that range.
      • If j > i, it sets a to the character represented by the Unicode value j.
      • Otherwise, it sets a to the character represented by the Unicode value i.
      • Then, it prints the character a followed by a space, using end=" " to prevent a newline.
    • The second inner loop, for j in range(65, k):, iterates from 65 up to k-1 (inclusive), with j taking on each value in that range.
      • If j > i, it sets b to the character represented by the Unicode value j.
      • Otherwise, it sets b to the character represented by the Unicode value i.
      • Then, it prints the character b followed by a space.
  4. After both inner loops finish, a print() statement is used to move to the next line, creating a newline in the output.
  5. The second outer loop starts with for i in range(66, k):.
    • This loop iterates from 66 to 69 (inclusive) with i taking on each value in that range.
  6. Inside the second outer loop, there are again two nested loops, similar to what was done in the first outer loop.
  7. The loops within the second outer loop perform similar actions as explained in steps 3 and 4.
  8. Once both outer loops and their respective inner loops finish executing, the entire pattern is printed.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
7 months ago

If you have any doubts regarding this article (Python Alphabet Pattern 29) please comment here. I will help you immediately.

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