Convert Binary to Decimal in JavaScript

Beginner
⏱️ 11 min read
📚 Updated: May 2026
🎯 2 Code examples + Try it
Base conversion

What you’ll learn

  • How positional notation turns a binary bit pattern into a decimal integer.
  • Two JavaScript styles: digit peel (integer that looks like 101010) and Horner on a string of "0" / "1".
  • Why integer doubling beats Math.pow(2, i) here, how to validate digits, and a browser live preview with parseInt(..., 2).

Overview

Binary uses powers of two from the rightmost bit (least significant). This page shows the same math two ways in JavaScript: peel digits from a “binary-looking” integer, or scan a string of '0' and '1' characters with Horner’s rule.

Two scripts

Digit peel (reference style, fixed) plus string Horner.

Live preview

Type a bit string; see decimal via parseInt(..., 2) for a quick check.

Fixes vs naive Math.pow

Exact integer weights, digit checks, and awareness of Number safe range.

Prerequisites

Loops, integer division and modulo, and the idea of place value (ones, twos, fours, …).

  • console.log, Number.isInteger, and string indexing for Example 2.
  • Optional: parseInt(s, 2) and binary literals 0b… (ES2015).

What does binary to decimal mean?

Each bit position i (starting at 0 on the right) contributes bi · 2i where bi ∈ {0, 1}. The decimal value is the sum of those contributions.

The reference stores the pattern as a normal decimal integer 101010 so each base-ten digit is one bit; the loop reads bits from right to left.

Binary base 2
Decimal base 10
Example 1010102 = 42

Expanded form

Reading 101010 from most to least significant bit (left to right as written),

1010102

1·25 + 0·24 + 1·23 + 0·22 + 1·21 + 0·20 = 32 + 8 + 2 = 42.

Intuition

10102 Decimal 10
Sum
8 + 2 = 10
1112 Decimal 7
Sum
4 + 2 + 1 = 7

Takeaway: each 1 flips on a power of two; each 0 skips that power.

Live preview

Enter a string of 0 and 1 characters (optional spaces). Uses parseInt(s, 2) for a quick decimal value. Empty or invalid characters are rejected.

For long strings, JavaScript may lose precision past 53 bits.

Live result
Press “Convert” to see the decimal value.

Algorithm (digit-stored form)

Goal: interpret a nonnegative integer whose decimal digits are only 0 or 1 as a binary pattern and return its decimal value.

Start value = 0, weight 1

Weight will double each step: 1, 2, 4, …

While the working number is nonzero

Take d = n % 10. If d is not 0 or 1, reject. Else add d * weight to value.

Shift

Divide n by 10, multiply weight by 2, repeat.

📜 Pseudocode

Pseudocode
function binaryDigitsToDecimal(n):  // n has only 0/1 decimal digits
    value ← 0
    weight ← 1
    while n > 0:
        d ← n mod 10
        if d not in {0, 1}: return error
        value ← value + d * weight
        n ← floor(n / 10)
        weight ← weight * 2
    return value
1

Digit peel (integer 101010, no Math.pow)

Matches the reference flow but uses an exact doubling weight instead of Math.pow(2, i), validates digits, and keeps the sum in a normal Number for typical bit lengths.

JavaScript
/** @param {number} n  nonnegative integer, digits only 0 or 1 */
function isBinaryDigitForm(n) {
  if (!Number.isFinite(n) || !Number.isInteger(n) || n < 0) {
    return false;
  }
  if (n === 0) {
    return true;
  }
  let t = n;
  while (t > 0) {
    const d = t % 10;
    if (d > 1) {
      return false;
    }
    t = Math.floor(t / 10);
  }
  return true;
}

/** Converts e.g. 101010 (decimal digits) to 42; returns -1 on invalid input */
function binaryDigitsToDecimal(binaryForm) {
  if (!isBinaryDigitForm(binaryForm)) {
    return -1;
  }
  let value = 0;
  let weight = 1;
  let n = binaryForm;

  while (n > 0) {
    const digit = n % 10;
    value += digit * weight;
    n = Math.floor(n / 10);
    weight *= 2;
  }

  return value;
}

const binaryForm = 101010;
const dec = binaryDigitsToDecimal(binaryForm);

if (dec < 0) {
  console.log("Invalid binary digit pattern.");
} else {
  console.log("Binary (digit form):", binaryForm);
  console.log("Decimal:", dec);
}
Try it Yourself

Explanation

The least significant decimal digit of 101010 is the least significant binary bit, so the first peeled digit pairs with weight 1, then 2, then 4, and so on.

weight *= 2;

Exact powers of two. Replaces Math.pow(2, i) without floating point.

if (d > 1) return false;

Reject invalid “binary” digits. A digit 29 must not be treated as a bit.

2

Horner’s method on a bit string

Natural when input arrives as text: scan most-significant bit first without reversing.

JavaScript
/** @param {string | null | undefined} s */
function binaryStringToDecimal(s) {
  if (s == null || s.length === 0) {
    return -1;
  }

  let v = 0;
  for (let i = 0; i < s.length; i++) {
    const c = s[i];
    if (c !== "0" && c !== "1") {
      return -1;
    }
    v = v * 2 + (c === "1" ? 1 : 0);
  }

  return v;
}

const bits = "101010";
const dec = binaryStringToDecimal(bits);

if (dec < 0) {
  console.log("Invalid binary string.");
} else {
  console.log("Binary (string):", bits);
  console.log("Decimal:", dec);
}
Try it Yourself

Explanation

Each step doubles the running value (shift left in binary) and adds the new bit.

v = v * 2 + (c === "1" ? 1 : 0);

Horner update. Same idea as v = (v << 1) | bit for integer bit variables in lower-level languages.

Optimization

Bit shifts. When you already have validated 0/1 ints, (value << 1) | bit (with a mask) can replace multiply-add on 32-bit-friendly paths—mind signed << rules in JavaScript.

Library path. For whole-string conversion, parseInt(s, 2) or Number.parseInt(s, 2) is built in; respect length and safe-integer limits, or use BigInt('0b' + s) for long patterns.

Interview: explain both LSD peel and Horner; mention validation and overflow.

❓ FAQ

The classroom trick stores the bit pattern as a decimal integer whose digits are only 0 and 1. The code peels digits with % 10. In real JavaScript you can also write the literal 0b101010 (ES2015) or parse a string with parseInt(s, 2) or BigInt('0b101010') depending on the task.
Floating-point exponents can round incorrectly for large i. Integer doubling (multiply a running power of two by 2) or bit shifts for 0/1 digits keep the sum exact for typical sizes.
That is not a valid binary digit. The samples validate each peeled digit and return an error sentinel so garbage digits are not treated as bits.
Scan left to right: start value 0, then for each character c, value = value * 2 + (c === '1' ? 1 : 0). That avoids reversing digits and matches how people read the string.
Yes. Past Number.MAX_SAFE_INTEGER (2^53 - 1), integer arithmetic is not exact. Use BigInt for wide bit strings, or validate length before using Number.
Proportional to the number of bits or digits: O(k) for k binary digits.

🔄 Input / output examples

Example 1 prints the digit-form value and decimal. Example 2 prints the string and decimal.

Input formMeaningDecimal
101010 (number)Six-bit pattern42
"101010" stringSame pattern42
102Invalid digit 2Error / -1 in sample

Edge cases and pitfalls

Confusing the digit-stored integer with a binary literal is the main conceptual trap; invalid digits and safe-integer limits are the main engineering traps.

Meaning

101010 in source code

That token is a decimal integer unless you use the 0b binary literal prefix. The peel routine interprets its decimal digits as bits.

Digits

Values outside {0,1}

Without validation, a digit like 9 would be treated as 9 · 2k in the peel loop—nonsense for binary.

Floats

Math.pow(2, i)

Can mis-round for large i. Prefer integer doubling or exact shifts.

Length

Very long bit strings

Horner on Number overflows past exact integer range; use BigInt or chunk the problem.

⏱️ Time and space complexity

ApproachTimeExtra space
Digit peel or Horner on k bitsO(k)O(1)

Both sample scripts use only a few scalars besides input storage.

Summary

  • Math: sum of bi 2i for bits bi.
  • Code: digit peel with doubling weight, or Horner on a string; avoid naive Math.pow for exact integers.
  • Watch-outs: meaning of 101010 in source, digit validation, and Number precision on long patterns.
Did you know?

The pattern 101010 in base two means 32 + 8 + 2 = 42 in base ten. In the first sample, that pattern is stored as the ordinary decimal integer 101010 so each base-ten digit is a binary bit; it is not the JavaScript binary literal 0b101010 (which already equals 42 in source code).

About the author

Mari Selvan M P
Mari Selvan M P 🔗

Developer, cloud engineer, and technical writer

  • Experience 12 years building web and cloud systems
  • Focus Full Stack Development, AWS, and Developer Education

I write practical tutorials so students and working developers can learn by doing—from databases and APIs to deployment on AWS.

9 people found this page helpful