Front-end Tutorials

Front-end Tutorials

HTMLCSSSassJavaScriptReactJS
CMS Tutorials

CMS Tutorials

WordPress
Tutorials expand

Java Number Pattern 37

Posted in Java Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 123 - Views
⏳ 4 mins
💬 1 Comment
Java Number Pattern 37

Photo Credit to CodeToFun

Java Number Pattern 37

Here`s a program that prints the above number pattern using Java Programming:

Demo.java
Copied
Copy To Clipboard
public class Demo
{
 public static void main(String[] args)
 {
  int i, j;
  for(i=1; i<=5; i++) 
  {
   for(j=i; j>1; j--)
    System.out.print(j);
   for(j=1; j<=i; j++) 
    System.out.print(j);
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
1
212
32123
4321234
543212345

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program defines a class named Demo.
  2. Inside the class, there's a main method, which is the entry point of the program. The public static void main(String[] args) signature indicates that this method can be called by the Java runtime and it accepts an array of strings as arguments (though in this program, the arguments are not used).
  3. Two integer variables i and j are declared without any initial values.
  4. The outer loop for(i=1; i<=5; i++) iterates through the values of i from 1 to 5 (inclusive).
  5. Inside the outer loop, there are three nested loops:
    • The first nested loop, for(j=i; j>1; j--), starts with the current value of i and decrements j until it's greater than 1. During each iteration of this loop, it prints the value of j. This loop is used to print a decreasing sequence of numbers from i down to 2.
    • The second nested loop, for(j=1; j<=i; j++), starts with 1 and increments j until it's less than or equal to the current value of i. During each iteration of this loop, it prints the value of j. This loop is used to print an increasing sequence of numbers from 1 up to i.
    • After both nested loops, System.out.println() is called to print a newline character, moving to the next line for the next iteration of the outer loop.
  6. As the outer loop progresses, it repeats the printing of decreasing and increasing sequences of numbers based on the current value of i.
  7. Once the outer loop completes all iterations (i.e., when i reaches 5), the program will finish.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

👨‍💻 Join our Community:

To get interesting news and instant updates on Front-End, Back-End, CMS and other Frameworks. Please Join the Telegram Channel:

Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

Buy me a coffee to make codetofun.com free for everyone.

Buy me a Coffee

Share Your Findings to All

Subscribe
Notify of
guest
1 Comment
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (Java Number Pattern 37) please comment here. I will help you immediately.

We make use of cookies to improve our user experience. By using this website, you agree with our Cookies Policy
AgreeCookie Policy