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Java Number Programs

Java Number Pattern 24

Posted in Java Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 124 - Views
⏳ 4 mins
💬 1 Comment
Java Number Pattern 24

Photo Credit to CodeToFun

Java Number Pattern 24

Here`s a program that prints the above number pattern using Java Programming:

Demo.java
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public class Demo
{
 public static void main(String[] args)
 {
  int i, j, k;
  k = 1;
  for(i=1; i<=5; i+=2)
  {
   for(j=5; j>=1; j--)
   {
    if(j > i)
     System.out.print(" ");
    else
     System.out.print(k++ +" ");  
   }
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
    1 
  2 3 4
5 6 7 8 9

🧠 How the Program Works

Let's break down the logic behind the code:

  1. public class Demo: Defines the class named Demo.
  2. public static void main(String[] args): This is the main method where the program execution starts. It takes an array of strings args as input, though it is not used in this program.
  3. int i, j, k;: Declares three integer variables i, j, and k to be used as loop counters and for printing numbers.
  4. k = 1;: Initializes the variable k with the value 1. This variable will be used to print sequential numbers.
  5. for (i = 1; i <= 5; i += 2) {: The outer loop iterates over i starting from 1 and incrementing by 2 in each iteration. This loop controls the number of rows (lines) printed.
  6. for (j = 5; j >= 1; j--) {: The inner loop iterates over j starting from 5 and decrementing by 1 in each iteration. This loop controls the spaces and numbers printed in each row.
  7. if (j > i): This condition checks whether the value of j is greater than the value of i. If true, a space is printed to create an indentation.
  8. System.out.print(k++ + " ");: If the condition in step 7 is false, this line prints the current value of k followed by a space. The post-increment operator k++ increases the value of k by 1 after it has been printed.
  9. System.out.println();: After each inner loop iteration, a newline character is printed to move to the next line.
  10. The outer loop continues its iterations, and with each iteration, the value of i increases by 2, resulting in a decreasing number of spaces and an increasing sequence of numbers printed on each line.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
10 months ago

If you have any doubts regarding this article (Java Number Pattern 24) please comment here. I will help you immediately.

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