Shape Rule
i..rows per row
Row 1 prints 12345, row 2 prints 2345, row 3 prints 345, and so on until a single 5.

The left-shifted descending number triangle changes the inner loop start value each row — a natural step after the classic descending triangle in Program 1. This tutorial covers the shape rule, loop structure, a live preview, algorithm steps, worked Java examples, edge cases, and complexity.
i..rows per row
Row 1 prints 12345, row 2 prints 2345, row 3 prints 345, and so on until a single 5.
1..rows
for (i = 1; i <= rows; i++) picks the starting digit for each row.
Start at i
for (j = i; j <= rows; j++) prints digits from i through rows.
Same line / next line
Digits use System.out.print(j); end each row with System.out.println().
1–20 rows
Pick a row count and draw the left-shifted triangle instantly in the browser.
Complexity
Total digit prints = n(n+1)/2; extra memory stays O(1).
A left-shifted descending number triangle keeps the longest row on top but shifts the start digit right each line. With rows = 5, the output is 12345, 2345, 345, 45, 5.
In Java the outer loop picks the row start i, the inner loop prints j from i to rows, then System.out.println() moves to the next line.
It teaches how changing the inner loop start value reshapes the output — a key step after Program 1.
On row i, print digits i through rows.
for (j = i; j <= rows; j++) — not j = 1.
System.out.print(j) in the inner loop; System.out.println() after.
Follow Program 1; continue to Program 3 (reverse descending triangle).
In short: for each row i from 1 to rows, print digits i..rows with System.out.print(j), then call System.out.println().
Given a positive integer rows, print a left-shifted descending triangle: each row i shows digits from i through rows, with the outer loop counting from 1 up to rows.
// rows = 5 (conceptual shape)
// 12345
// 2345
// 345
// 45
// 5 | Item | Type | Description |
|---|---|---|
rows | int | Number of triangle lines to print (typically ≥ 1). |
| Printed output | text | Each row prints i..rows; the top row has rows digits, the bottom row has one digit. |
for i from 1 to rows:
for j from i to rows:
print j (no newline)
print newline | Approach | Idea | Best for |
|---|---|---|
| Nested loops | Outer rows + inner digits | Learning and interviews |
StringBuilder row builder | Append digits then println the row | Shorter production-style demos |
| Goal | Pattern |
|---|---|
| Walk each row | for (i = 1; i <= rows; i++) |
Print digits i..rows | for (j = i; j <= rows; j++) System.out.print(j); |
| End the row | System.out.println(); |
| One-line row shortcut | StringBuilder.append(j) loop |
| Program 1 variant | for (i = rows; i >= 1; i--) with j = 1..i |
Same triangle — different ways to emit characters.
same linePrints a digit without moving to the next line
new lineEnds the current row after all digits are printed
whole rowBuilds digits i..rows with StringBuilder.append(j)
loops firstMaster nested loops before the StringBuilder shortcut
Reach for this pattern when teaching how the inner loop start value changes the shape.
Natural follow-up after Program 1 — changes the inner loop start value.
Outer/inner bound practice with an immediate visual check.
Combine loops with Scanner for a flexible row count.
Compare Program 1 (classic descending) and Program 3 (reverse descending) next.
This is a console teaching pattern — not how you build modern app screens.
Key benefit: one small program that locks in nested loops, output sequencing, and O(n²) thinking.
Choose a row count between 1 and 20 and draw the left-shifted number triangle in the browser.
Three complete Java programs — fixed rows, user input, and a StringBuilder shortcut. Click View Output to reveal sample console results.
Print five rows of the left-shifted triangle with nested loops.
rows = 5Hard-coded height — ideal for first demos and screenshots.
public class LeftShiftedNumberTriangle {
public static void main(String[] args) {
int rows = 5;
for (int i = 1; i <= rows; i++) {
for (int j = i; j <= rows; j++) {
System.out.print(j);
}
System.out.println();
}
}
} When i = 1, the inner loop prints 12345. When i = 2, it prints 2345, and so on until i = 5 prints 5. System.out.println() after the inner loop starts the next row.
Let the user choose the height at runtime.
Read the row count with sc.nextInt() (call sc.hasNextInt() first in real apps).
import java.util.Scanner;
public class LeftShiftedNumberTriangleInput {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
System.out.print("Enter the number of rows: ");
int rows = sc.nextInt();
for (int i = 1; i <= rows; i++) {
for (int j = i; j <= rows; j++) {
System.out.print(j);
}
System.out.println();
}
sc.close();
}
} Same nested-loop core as Example 1; only the source of rows changes. Non-numeric input leaves rows unset if you ignore Scanner’s return value — always check it in safer labs.
Same left-shifted shape by building each row in a StringBuilder before printing.
StringBuilder Row BuilderAppend each digit to a StringBuilder, then print the full row with println.
public class LeftShiftedNumberString {
public static void main(String[] args) {
int rows = 5;
for (int i = 1; i <= rows; i++) {
StringBuilder row = new StringBuilder();
for (int j = i; j <= rows; j++) {
row.append(j);
}
System.out.println(row);
}
}
} StringBuilder.append(j) collects each digit, then println prints the whole row at once. Same nested-loop structure as Example 1; a compact alternative to repeated System.out.print(j). Keep either style for exams that want both loop bounds visible.
System.out is built in; use Scanner when reading input. Set rows (fixed or from input).
for (i = 1; i <= rows; i++) selects the starting digit for each row.
for (j = i; j <= rows; j++) prints digits i..rows with System.out.print(j).
System.out.println() ends the row so the next outer iteration starts fresh.
Total digit prints: 1+2+…+n = n(n+1)/2 — O(n²) time, O(1) extra memory.
rows = 4Trace each outer-loop value of i (counting up) and the inner j range on each row.
i | Inner j range | Printed row | Digits this row |
|---|---|---|---|
1 | 1..4 | 1234 | 4 |
2 | 2..4 | 234 | 3 |
3 | 3..4 | 34 | 2 |
4 | 4..4 | 4 | 1 |
Total digit prints: 4 + 3 + 2 + 1 = 10 = 4×5/2.
Where this tiny pattern (and its loop structure) shows up beyond the homework prompt.
Clearest visual proof that outer and inner bounds interact.
Example: change j <= rows and watch the shape change.
Foundation for inverted, pyramid, diamond, and hollow variants.
Example: change inner start from j = i to j = 1 and compare with Program 1.
Practice System.out.print vs row newline without complex math.
Example: put System.out.println() inside the inner loop by mistake.
Swap digits for letters, stars, or spaced output once the loop works.
Example: print j + " " for spaced digits on each row.
Triangular totals make O(n²) concrete for beginners.
Example: count printed digits for n = 10 → 55.
Pair the pattern with Scanner return checks and positive-row checks.
Example: reject rows <= 0 and re-prompt.
Pro Tip: when an interviewer asks for patterns, explain the outer/inner roles first — then write the loops. The story matters as much as the code.
Why this pattern earns a permanent spot in beginner C courses.
Wrong bounds show up immediately as a broken staircase.
Only loops and console output — no arrays or math libraries.
Invert, center, hollow, or change the fill character with small edits.
Streaming output needs no storage beyond loop counters.
Pro Tip: learn the nested-loop version first; treat the StringBuilder row builder as a polish shortcut afterward.
Small habits that keep number-pattern code clean.
Use rows (or n) and keep i/j for row/column — or rename to row/col.
ScannerCall sc.hasNextInt() so bad input does not leave rows uninitialized.
Only call System.out.println() after the inner loop finishes the row.
for (j = i; j <= rows; j++) matches “row i prints digits i..rows” naturally.
Trace rows = 3 on paper before coding larger demos.
Pro Tip: if the output is a vertical list of single digits, you almost certainly put System.out.println() inside the inner loop.
Mistakes that commonly break left-shifted number patterns.
Each digit lands on its own line — you get a column, not a triangle.
→ Use System.out.print(j) for digits; System.out.println() only after the inner loop.
j = 1 prints Program 1’s shape; j <= i prints a growing triangle.
→ For this shape, keep for (j = i; j <= rows; j++).
Omitting System.out.println() glues every digit onto one endless line.
→ Always end the row after the inner loop.
Letters or empty input leave rows uninitialized.
→ Prefer hasNextInt() and re-prompt on failure.
Switching to i = 0 without adjusting the inner bound prints an empty first row or wrong counts.
→ If 0-based, start inner at j = i and end at rows - 1 or adjust bounds.
Check these inputs before calling the solution done.
Output is just 1 on one line.
Outer loop never runs — print nothing or show a message.
rows < 0Treat as invalid; re-prompt instead of silent empty output.
Output grows as n²/2 characters — fine for labs, noisy for huge n.
Unchecked Scanner leaves rows unset — call sc.hasNextInt() first.
Try System.out.print(j + " ") for spaces between numbers.
Try these variations to lock in the pattern.
sc.hasNextInt() until rows >= 1System.out.print(j + " ") between digitsn(n+1)/2 — hence O(n²) time.System.out.print(j) stays on the line; System.out.println() advances — mix them carefully.rows > 0 for interactive programs; rows = 1 should print a single 1.Quick Takeaway: outer loop picks start i, inner loop prints digits i..rows, then break the line — that is the whole pattern.
| Program | Time | Extra space |
|---|---|---|
| Nested loops (Examples 1–2) | O(rows²) | O(1) |
StringBuilder row builder (Example 3) | O(rows²) | O(rows) per row string (temporary) |
The left-shifted descending number triangle is a small nested-loop exercise with lasting payoff: changing the inner start value, System.out.print vs row newline, and O(n²) intuition. Master the classic two-loop version, then optionally build each row with a StringBuilder.
Practice the three examples above, then continue to Program 3 for the reverse descending number triangle.
Row i prints i..rows — keep System.out.print(j) for digits and System.out.println() for the break, and validate row counts when reading input.
j = i inner start before codingSystem.out.print(j) for digits and System.out.println() after each rowrows ≥ 1 for interactive programssc.hasNextInt() before using rowsSystem.out.println() inside the inner digit loopj = 1 when you meant left-shifted shaperows = 1 edge casePrint the triangle the beginner-friendly way.
Row i prints i..rows
DefinitionControls each row
Codej = i, not j = 1
CodeEnds each row
I/OO(n²) time
AnalysisEach row starts at i and prints through rows, so the left edge shifts right each line — still O(n²) total prints for n rows.
Move on to the reverse descending number triangle in the Java number-pattern series.
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