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Java Number Pattern 19

Posted in Java Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 121 - Views
⏳ 4 mins
💬 1 Comment
Java Number Pattern 19

Photo Credit to CodeToFun

Java Number Pattern 19

Here`s a program that prints the above number pattern using Java Programming:

Demo.java
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public class Demo
{
 public static void main(String[] args)
 {
  int i, j;
  for(i=5; i>=1; i--)
  {
   for(j=i; j<=5; j++)
    System.out.print(j + " ");
   for(j=1; j<i; j++)
    System.out.print(5 + " ");
   System.out.println();
  }
 }
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
5 5 5 5 5
4 5 5 5 5
3 4 5 5 5
2 3 4 5 5
1 2 3 4 5

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program defines a class named Demo.
  2. Inside the class, there's a public static void main(String[] args) method. This is the entry point of the program. The program execution starts here.
  3. Two integer variables, i and j, are declared. These will be used in the loops for iteration.
  4. There's an outer for loop with the condition i=5; i>=1; i--. This loop iterates from i=5 down to i=1. It controls the number of rows in the output pattern.
  5. Inside the outer loop, there are two nested for loops and a System.out.println() statement.
  6. The first nested for loop has the condition j=i; j<=5; j++. It iterates from the current value of i to 5. This loop is responsible for printing the values in increasing order.
  7. Inside this loop, System.out.print(j + " ") prints the current value of j, followed by a space.
  8. The second nested for loop follows with the condition j=1; j<i; j++. It iterates from j=1 up to (but not including) the current value of i. This loop is responsible for printing the value 5 in case of the decreasing part of the pattern.
  9. Inside this loop, System.out.print(5 + " ") prints the value 5, followed by a space.
  10. After both nested for loops, a System.out.println() statement is executed to move the cursor to the next line, creating a new row in the output pattern.
  11. The outer for loop continues to the next iteration, and steps 6-10 are repeated for the next value of i.
  12. This process continues until i becomes less than 1, which ends the outer loop.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
1 year ago

If you have any doubts regarding this article (Java Number Pattern 19), please comment here. I will help you immediately.

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