In C++, strcpy() copies a whole C-string into another array, including the ending '\0'. After the call, dest holds the same text as source.
Both arguments are required. dest must already be large enough for every character plus the '\0'. strcpy() does not grow the array, and the two arrays must not overlap. Include <cstring>.
The first argument is where the copy goes. The second argument is the text you copy.
strcpy(dest, "Hello");| Call | What it does |
|---|---|
strcpy(dest, "Hello") | Copies Hello, including the ending null, into dest. |
char* strcpy(char* destination, const char* source);| Parameter | Description |
|---|---|
| dest | Required. The array you copy into. It must already be large enough. |
| source | Required. The C-string you copy from. It is not changed. |
| Return Value | Description |
|---|---|
| dest | The same pointer you passed in, now holding the copy. |
strcpy()Copy a greeting into a char array.
#include <iostream>
#include <cstring>
int main() {
char dest[50];
const char* src = "Hello, C++!";
strcpy(dest, src);
std::cout << dest << '\n';
return 0;
}dest is a writable buffer with room for the text.strcpy copies characters from src, then '\0'.dest shows the copied string.The destination is a separate copy you can edit.
#include <iostream>
#include <cstring>
int main() {
const char* src = "Take the test.";
char dest[40];
strcpy(dest, src);
dest[0] = 'M';
std::cout << "src: " << src << '\n';
std::cout << "dest: " << dest << '\n';
return 0;
}dest[0] does not change src.std::stringSame idea without sizing a buffer yourself.
#include <iostream>
#include <string>
int main() {
std::string src = "Hello, C++!";
std::string dest = src;
std::cout << dest << '\n';
return 0;
}'\0' or buffer length math.strcpy for C APIs; prefer std::string in new C++.Count characters until one from a reject set appears.
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