In C++, strcat() joins two C-strings. It copies the second string onto the end of the first, starting where the old '\0' was, then writes a new '\0'.
Both strings are required. The first array must already have free space for the added characters and that new '\0'. strcat() does not grow the array, and the two strings must not overlap. Include <cstring>.
The first string is the one that grows. The second string is copied onto its end.
strcat(dest, "C++");| Call | What it does |
|---|---|
strcat(dest, "C++") | Adds C++ onto the end of dest. |
char* strcat(char* destination, const char* source);| Parameter | Description |
|---|---|
| dest | Required. The C-string you add onto. It must already have room for the new characters. |
| source | Required. The C-string you copy from. It is not changed. |
| Return Value | Description |
|---|---|
| dest | The same pointer you passed in. It now holds both strings. |
strcat()Append "World!" onto "Hello ".
#include <iostream>
#include <cstring>
int main() {
char dest[50] = "Hello ";
const char* src = "World!";
strcat(dest, src);
std::cout << dest << '\n';
return 0;
}dest starts as "Hello " (with room left in the array).strcat finds the end of dest and copies src there."Hello World!" ending with '\0'.Call strcat again to keep building one buffer.
#include <iostream>
#include <cstring>
int main() {
char message[80] = "C++";
strcat(message, " ");
strcat(message, "Tutorial");
std::cout << message << '\n';
return 0;
}"Tutorial".std::stringSame idea without managing a fixed buffer yourself.
#include <iostream>
#include <string>
int main() {
std::string text = "Hello ";
text += "World!";
std::cout << text << '\n';
return 0;
}std::string grows as needed.+= appends like strcat, but safer for beginners.strcat for C-style APIs; prefer std::string in new C++.Find the first occurrence of a character in a C-string.
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