C++ Number Pattern 61

Posted in C++ Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 82 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

C++ Number Pattern 61

Here`s a program that prints the above number pattern using C++ Programming:

example.cpp

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#include <iostream>
using namespace std;

int main() {
  int num = 86523;
  int reverse = 0;
  while (num != 0) {
    reverse = reverse * 10;
    reverse = reverse + (num % 10);
    cout << reverse << "\n";
    num = num / 10;
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

🧠 How the Program Works

Let's break down the logic behind the code:

#include <iostream>: This line includes the input-output stream library, which provides functionality for input and output operations like cin and cout.
using namespace std;: This line allows you to use the standard namespace (std) without explicitly specifying it for each element. It makes it easier to use elements from the standard library, such as cout and endl.
int main(): This is the starting point of the C++ program. All C++ programs start execution from the main() function.
int num = 86523;: This line declares and initializes an integer variable num with the value 86523.
int reverse = 0;: This line declares and initializes another integer variable reverse with the value 0. This variable will be used to store the reverse of the num variable.
while (num != 0): This starts a while loop that will continue executing as long as the value of num is not equal to 0. In other words, the loop will continue until all digits of the original number are processed.
Inside the while loop:
1. reverse = reverse * 10;: In each iteration, the reverse variable is multiplied by 10, shifting its digits to the left. This is done to accommodate the next digit to be added in the reverse number.
2. reverse = reverse + (num % 10);: The last digit of the num variable is extracted using the modulo operator % 10. This digit is then added to the reverse variable, effectively creating the reversed number digit by digit.
3. cout << reverse << "\n";: The current value of the reverse variable (partial reversed number) is printed on the screen.
4. num = num / 10;: The last digit of the num variable is removed by performing an integer division by 10. This is done to move to the next digit for the next iteration.
After the while loop finishes executing, the program continues to the return 0; statement, which signifies the successful completion of the main() function. The program then terminates.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!