C++ Number Pattern 13

Posted in C++ Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 112 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

C++ Number Pattern 13

Here`s a program that prints the above number pattern using C++ Programming:

example.cpp

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#include <iostream>
using namespace std;

int main() {
  int i, j;
  for (i = 5; i >= 1; i--) {
    if (i % 2 == 0) {
      for (j = i; j >= 1; j--)
        cout << j;
    } else {
      for (j = 1; j <= i; j++)
        cout << j;
    }
    cout << "\n";
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

🧠 How the Program Works

Let's break down the logic behind the code:

The program starts by including the necessary header file <iostream>, which allows input/output operations in C++. The using namespace std; statement is used to avoid typing std:: before every standard library object.
The main() function is the entry point of the program. It has a return type of int, indicating that it should return an integer value.
Two integer variables i and j are declared to be used in the program.
The for loop is used to iterate from i=5 to i>=1, with i-- decrementing i by 1 in each iteration.
Inside the for loop, there is an if statement that checks if i is divisible by 2 (i.e., if i is an even number). If the condition i%2 == 0 evaluates to true, the following block of code executes:

a. Another for loop is used, starting with j=i and decrementing j by 1 in each iteration until j>=1.
b. Inside this loop, the value of j is printed using the cout statement. This prints the current value of j on the console.

If the if condition in step 5 evaluates to false (i.e., i is an odd number), the following block of code executes:
- a. Another for loop is used, starting with j=1 and incrementing j by 1 in each iteration until j<=i.
- b. Inside this loop, the value of j is printed using the cout statement. This prints the current value of j on the console.
After printing the numbers based on the value of i, a newline character "\n" is printed using cout to move to the next line.
The program continues to the next iteration of the outer for loop until i reaches 1.
Once the outer for loop completes, the program reaches the return 0; statement, indicating that the program executed successfully and is returning an integer value of 0 to the operating system.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the number pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!