C++ Alphabet Pattern 31

Posted in C++ Tutorial

Updated on Jan 10, 2024

By Mari Selvan

👁️ 102 - Views

⏳ 4 mins

💬 1 Comment

Photo Credit to CodeToFun

C++ Alphabet Pattern 31

Here`s a program that prints the above alphabet pattern using C++ Programming:

example.cpp

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#include <iostream>
using namespace std;

int main() {
  int i, j, k;
  for (i = 65; i <= 69; i++) {
    for (j = 65; j <= 69; j++) {
      if (i == j)
        cout << char(j);
      else
        cout << " ";
    }
    for (k = 68; k >= 65; k--) {
      if (i == k)
        cout << char(k);
      else
        cout << " ";
    }
    cout << "\n";
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output

A       A
 B     B
  C   C
   D D
    E

🧠 How the Program Works

Let's break down the logic behind the code:

The program starts by including the necessary header file iostream, which provides input/output stream functionality in C++.
The line using namespace std; allows us to use names from the std namespace directly, without specifying the namespace explicitly.
The main() function is the entry point of the program.
Three integer variables i, j, and k are declared to be used in the loops and comparisons.
The outer for loop is responsible for iterating over the rows of the diamond pattern. It initializes i with 65 (ASCII value for 'A') and continues until i reaches 69 (ASCII value for 'E').
Inside the outer loop, there are two nested for loops. The first inner for loop initializes j with 65 and continues until j reaches 69. It iterates over the columns before the center of the diamond pattern.
In the first inner for loop, there's an if statement that checks if i is equal to j. If they are equal, it means that we are on the diagonal of the diamond, so the character corresponding to the ASCII value of j is printed using cout.
If i is not equal to j, a space character is printed instead.
The second inner for loop initializes k with 68 (ASCII value for 'D') and continues until k reaches 65 (ASCII value for 'A'). It iterates over the columns after the center of the diamond pattern.
In the second inner for loop, there's another if statement that checks if i is equal to k. If they are equal, it means that we are on the diagonal of the diamond, so the character corresponding to the ASCII value of k is printed using cout.
If i is not equal to k, a space character is printed instead.
After the two inner for loops have finished executing, a newline character (\n) is printed using cout to move to the next row of the diamond pattern.
Steps 6 to 12 are repeated for each row of the diamond pattern.
Once the outer for loop finishes executing, the program reaches the end of the main() function, and the value 0 is returned to indicate successful program execution.
The program terminates, and the diamond pattern is displayed on the console.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!