Shape Rule
Continuous k++
Row 1 prints 1, row 2 prints 2 3, row 3 prints 4 5 6, and so on without restarting.

The continuous number triangle uses a running counter k so digits keep increasing across rows — a natural step after the fill-with-5 pattern in Program 19. This tutorial covers the shape rule, counter logic, a live preview, algorithm steps, worked C examples, edge cases, and complexity.
Continuous k++
Row 1 prints 1, row 2 prints 2 3, row 3 prints 4 5 6, and so on without restarting.
1..rows
for (i = 1; i <= rows; i++) makes row i print i numbers.
k++ each print
printf("%d ", k++) prints k then increments — value carries to the next row.
Same line / next line
Numbers use printf("%d ", k++); end each row with printf("\n").
1–15 rows
Pick a row count and draw the continuous counter triangle instantly in the browser.
Complexity
Total prints = rows(rows+1)/2; extra memory stays O(1).
A continuous number triangle prints an ascending counter across rows — numbers never restart at 1 on each new line. With rows = 4, the output is 1, 2 3, 4 5 6, 7 8 9 10.
In C you declare k = 1 once, print k++ in the inner loop for i iterations per row, then printf("\n") ends each row.
It introduces a running counter variable — a key step after Program 19 and before jump-number patterns.
Declare k = 1 once before both loops.
Print then increment — sequence continues across rows.
printf("%d ", k++) in the inner loop; printf("\n") after.
Follow Program 19; continue to Program 21 (jump number triangle).
In short: set k = 1 once, for each row i print k++ for i numbers, then call printf("\n").
Given a positive integer rows, print a continuous number triangle: row i prints i numbers from a running counter k that starts at 1 and increments with k++ on every print.
// rows = 4 (conceptual shape)
// 1
// 2 3
// 4 5 6
// 7 8 9 10 | Item | Type | Description |
|---|---|---|
rows | int | Number of triangle lines to print (typically ≥ 1). |
k | int | Running counter — declared once, incremented each print. |
| Printed output | text | Row i has i spaced numbers — continuous sequence. |
k = 1
for i from 1 to rows:
for j from 1 to i:
print k then k++
print newline | Approach | Idea | Best for |
|---|---|---|
| Running counter k++ | 1, 2 3, 4 5 6, … | Learning and interviews |
| User-input rows | scanf("%d", &rows); | Flexible console programs |
| Custom start k | k = 10 before loops | Shift the whole sequence |
| Goal | Pattern |
|---|---|
| Walk each row | for (i = 1; i <= rows; i++) |
| Init counter | int k = 1; before both loops |
| Print and step | printf("%d ", k++); |
| End the row | printf("\n"); |
| Custom start | int k = 10; to shift sequence |
| User input | scanf("%d", &rows); |
Same continuous triangle — different ways to control the counter.
counterPrint k then increment — sequence continues
k = 1Before both loops — not inside outer loop
k = 10Shift start value in Example 3
no resetDo not reset k each row for continuous output
Reach for this pattern when teaching running counters and continuous sequences inside nested loops.
Natural follow-up after Program 19 — introduces a single running counter.
Outer/inner bound practice with an immediate visual check.
Combine loops with scanf for a flexible row count.
Compare Program 19 (fill-with-5) and Program 21 (jump number triangle) next.
This is a console teaching pattern — not how you build modern app screens.
Key benefit: one small program that locks in nested loops, output sequencing, and O(n²) thinking.
Choose a row count between 1 and 15 and draw the continuous number triangle in the browser.
Three complete C programs — fixed row count, user input, and custom start value for k. Click View Output to reveal sample console results.
Print four rows of the continuous counter triangle with k++.
rows = 4Hard-coded height — ideal for first demos and screenshots.
#include <stdio.h>
int main() {
int rows = 4;
int i, j;
int k = 1;
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j)
printf("%d ", k++);
printf("\n");
}
return 0;
} When i = 1, k prints once as 1. When i = 2, k prints 2 then 3. When i = 4, k runs from 7 to 10 — the counter never resets. printf("\n") after the inner loop starts the next row.
Read the row count with scanf instead of hard-coding 4.
Read rows with scanf("%d", &rows); k still starts at 1.
#include <stdio.h>
int main() {
int rows;
int i, j;
int k = 1;
printf("Enter the number of rows: ");
scanf("%d", &rows);
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j)
printf("%d ", k++);
printf("\n");
}
return 0;
} Same nested-loop core as Example 1; only the source of rows changes. k is still declared once before the loops. Non-numeric input leaves rows unset if you ignore scanf’s return value — always check it in safer labs.
Start the counter from a value other than 1.
k = 10Shift the whole sequence by starting k at 10 instead of 1.
#include <stdio.h>
int main() {
int rows = 4;
int i, j;
int k = 10;
for (i = 1; i <= rows; ++i) {
for (j = 1; j <= i; ++j)
printf("%d ", k++);
printf("\n");
}
return 0;
} Change only the initial value of k — the inner loop and k++ logic stay the same. The sequence continues from 10 instead of 1.
#include <stdio.h> brings in printf / scanf. Set rows and k = 1.
for (i = 1; i <= rows; i++) makes row i print i numbers.
printf("%d ", k++) prints k then increments — value carries to the next row.
printf("\n") ends the row so the next outer iteration starts fresh.
Total prints: rows(rows+1)/2 — O(n²) time, O(1) extra memory.
rows = 4Trace each outer-loop value of i, the starting k, and the numbers printed on each row.
i | Start k | Numbers printed | Row output |
|---|---|---|---|
1 | 1 | 1 | 1 |
2 | 2 | 2, 3 | 2 3 |
3 | 4 | 4, 5, 6 | 4 5 6 |
4 | 7 | 7, 8, 9, 10 | 7 8 9 10 |
Total number prints: 1 + 2 + 3 + 4 = 10 = 4×5/2.
Where this tiny pattern (and its loop structure) shows up beyond the homework prompt.
Clearest visual proof that outer and inner bounds interact.
Example: change j <= i and watch the shape change.
Foundation for inverted, pyramid, diamond, and hollow variants.
Example: use (i + j) % 2 for row+column parity grids.
Practice printf vs row newline without complex math.
Example: put printf("\n") inside the inner loop by mistake.
Swap digits for letters, stars, or spaced output once the loop works.
Example: print j + " " for spaced digits on each row.
Triangular totals make O(n²) concrete for beginners.
Example: count printed digits for n = 10 still → 55.
Pair the pattern with scanf return checks and positive-row checks.
Example: reject rows <= 0 and re-prompt.
Pro Tip: when an interviewer asks for patterns, explain the outer/inner roles first — then write the loops. The story matters as much as the code.
Why this pattern earns a permanent spot in beginner C courses.
Wrong bounds show up immediately as a broken staircase.
Only loops and console output — no arrays or math libraries.
Invert, center, hollow, or change the fill character with small edits.
Streaming output needs no storage beyond loop counters.
Pro Tip: learn k = 1 before the loops first; compare with custom start in Example 3.
Small habits that keep number-pattern code clean.
Declare k once before both loops — not inside the outer loop.
scanfCheck the return value so bad input does not leave rows uninitialized.
Only call printf("\n") after the inner loop finishes the row.
Write row i, start k, and each k++ step before coding.
Trace rows = 4 on paper before coding larger demos.
Pro Tip: if the output is a vertical list of single digits per line, you almost certainly put printf("\n") inside the inner loop.
Mistakes that commonly break continuous number patterns.
Each digit lands on its own line — you get a column, not a triangle.
→ Use printf("%d ", k++); printf("\n") only after the inner loop.
k resets each row and the sequence restarts at 1.
→ Declare int k = 1; once before both loops.
Incrementing in the wrong place skips or duplicates numbers.
→ Use post-increment inside printf("%d ", k++).
Omitting printf("\n") glues every number onto one endless line.
→ Always end the row after the inner loop.
Letters or empty input leave rows uninitialized.
→ Check scanf return value and re-prompt on failure.
Check these inputs before calling the solution done.
Output is just 1 on one line.
Outer loop never runs — print nothing or show a message.
rows < 0Treat as invalid; re-prompt instead of silent empty output.
Output grows as n² characters — fine for labs, noisy for huge n.
Unchecked scanf leaves rows unset — check the return value.
Declaring k inside the outer loop restarts the sequence — not continuous.
Without k++, the same number prints repeatedly on each row.
Try these variations to lock in the pattern.
k inside outer looprows(rows+1)/2 — O(n²) for n rows.printf("%d ", k++) stays on the line; printf("\n") advances — mix them carefully.rows > 0 for interactive programs; rows = 1 should print a single 1.Quick Takeaway: declare k = 1 once, print k++ for i numbers per row, then break the line.
| Program | Time | Extra space |
|---|---|---|
| Nested loops (Examples 1–2) | O(rows²) | O(1) |
| Custom start (Example 3) | O(rows²) | O(1) |
The continuous number triangle is a compact lesson in running counters: declare k once, print k++ in the inner loop, and let the sequence continue across rows. Master the fixed-rows version, then try user input and a custom start value.
Practice the three examples above, then continue to Program 21 for the jump number triangle.
Keep k outside the outer loop — use k++ inside printf("%d ", k++) and validate rows when reading input.
k = 1 before both loopsprintf("%d ", k++) in the inner looprows ≥ 1 for interactive programsscanf return value before using rowsprintf("\n") inside the inner digit loopk inside the outer loopk++ after each printrows = 1 edge casePrint the pattern the beginner-friendly way.
k++ continuous
DefinitionOnce before loops
CodePrint then increment
CodeRow i prints i nums
ShapeO(n²) time
AnalysisA single counter k starts at 1 and increments with k++ on every print — numbers continue across rows instead of restarting. Total prints still equal n(n+1)/2 for n rows.
Move on to the jump number triangle in the C number-pattern series.
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