Left-Shifted Number Triangle in C

Beginner
⏱️ 8 min read
📚 Updated: Aug 2026
🎯 3 Code Examples
🚀 Live Preview
Inner Loop Start

What You’ll Learn

The left-shifted descending number triangle changes the inner loop start value each row — a natural step after the classic descending triangle in Program 1. This tutorial covers the shape rule, loop structure, a live preview, algorithm steps, worked C examples, edge cases, and complexity.

Shape Rule

i..rows per row

Row 1 prints 12345, row 2 prints 2345, row 3 prints 345, and so on until a single 5.

Outer Loop

1..rows

for (i = 1; i <= rows; i++) picks the starting digit for each row.

Inner Loop

Start at i

for (j = i; j <= rows; j++) prints digits from i through rows.

printf vs newline

Same line / next line

Digits use printf("%d", j); end each row with printf("\n").

Live Preview

1–20 rows

Pick a row count and draw the left-shifted triangle instantly in the browser.

O(n²)

Complexity

Total digit prints = n(n+1)/2; extra memory stays O(1).

Introduction

A left-shifted descending number triangle keeps the longest row on top but shifts the start digit right each line. With rows = 5, the output is 12345, 2345, 345, 45, 5.

In C the outer loop picks the row start i, the inner loop prints j from i to rows, then printf("\n") moves to the next line.

Why it matters?

It teaches how changing the inner loop start value reshapes the output — a key step after Program 1.

Key Highlights

Row Start = i

On row i, print digits i through rows.

Inner Starts at i

for (j = i; j <= rows; j++) — not j = 1.

Print Then Break

printf("%d", j) in the inner loop; printf("\n") after.

Series Foundation

Follow Program 1; continue to Program 3 (reverse descending triangle).

In short: for each row i from 1 to rows, print digits i..rows with printf("%d", j), then call printf("\n").

📝 Problem & Approach

Given a positive integer rows, print a left-shifted descending triangle: each row i shows digits from i through rows, with the outer loop counting from 1 up to rows.

c
// rows = 5 (conceptual shape)
// 12345
// 2345
// 345
// 45
// 5

Inputs & Outputs

ItemTypeDescription
rowsintNumber of triangle lines to print (typically ≥ 1).
Printed outputtextEach row prints i..rows; the top row has rows digits, the bottom row has one digit.

Minimal workflow

Pseudocode
for i from 1 to rows:
    for j from i to rows:
        print j (no newline)
    print newline

Approach comparison

ApproachIdeaBest for
Nested loopsOuter rows + inner digitsLearning and interviews
putchar('0' + j) loopEmit digits with putchar instead of printfShorter production-style demos

⚡ Quick Reference

GoalPattern
Walk each rowfor (i = 1; i <= rows; i++)
Print digits i..rowsfor (j = i; j <= rows; j++) printf("%d", j);
End the rowprintf("\n");
One-line row shortcutputchar('0' + j) loop
Program 1 variantfor (i = rows; i >= 1; i--) with j = 1..i

📋 printf vs newline vs putchar shortcut

Same triangle — different ways to emit characters.

printf
same line

Prints a digit without moving to the next line

Newline
new line

Ends the current row after all digits are printed

putchar
whole row

Writes digits i..rows with putchar('0' + j)

Learning tip
loops first

Master nested loops before the putchar shortcut

Context

When This Pattern Shows Up

Reach for this pattern when teaching how the inner loop start value changes the shape.

  1. First lab exercise

    Natural follow-up after Program 1 — changes the inner loop start value.

  2. Nested-loop warm-up

    Outer/inner bound practice with an immediate visual check.

  3. Console I/O practice

    Combine loops with scanf for a flexible row count.

  4. Gateway to variants

    Compare Program 1 (classic descending) and Program 3 (reverse descending) next.

  5. Not a UI layout tool

    This is a console teaching pattern — not how you build modern app screens.

Key benefit: one small program that locks in nested loops, output sequencing, and O(n²) thinking.

🔮 Live Preview

Choose a row count between 1 and 20 and draw the left-shifted number triangle in the browser.

Try 5, 7, or 10. Larger values still work up to 20.

Live result
Press "Draw pattern".

Examples Gallery

Three complete C programs — fixed rows, user input, and a putchar shortcut. Click View Output to reveal sample console results.

📚 Getting Started

Print five rows of the left-shifted triangle with nested loops.

Example 1 — Fixed rows = 5

Hard-coded height — ideal for first demos and screenshots.

c
#include <stdio.h>

int main() {
    int rows = 5;
    int i, j;

    for (i = 1; i <= rows; ++i) {
        for (j = i; j <= rows; ++j) {
            printf("%d", j);
        }
        printf("\n");
    }

    return 0;
}

How It Works

When i = 1, the inner loop prints 12345. When i = 2, it prints 2345, and so on until i = 5 prints 5. printf("\n") after the inner loop starts the next row.

📈 Practical Variant

Let the user choose the height at runtime.

Example 2 — User Input Version

Read the row count with scanf("%d", &rows) (check the return value in real apps).

c
#include <stdio.h>

int main() {
    int rows;
    int i, j;

    printf("Enter the number of rows: ");
    scanf("%d", &rows);

    for (i = 1; i <= rows; ++i) {
        for (j = i; j <= rows; ++j) {
            printf("%d", j);
        }
        printf("\n");
    }

    return 0;
}

How It Works

Same nested-loop core as Example 1; only the source of rows changes. Non-numeric input leaves rows unset if you ignore scanf’s return value — always check it in safer labs.

⚡ putchar Shortcut

Same left-shifted shape with putchar instead of printf.

Example 3 — putchar('0' + j)

Write each digit with putchar, then end the row with putchar('\n').

c
#include <stdio.h>

int main() {
    int rows = 5;
    int i, j;

    for (i = 1; i <= rows; ++i) {
        for (j = i; j <= rows; ++j) {
            putchar('0' + j);
        }
        putchar('\n');
    }

    return 0;
}

How It Works

putchar('0' + j) writes one digit when j is 1..9 without a format string. Same nested-loop structure as Example 1; a leaner alternative to printf("%d", j). Keep either style for exams that want both loop bounds visible.

🧠 How the Algorithm Prints Rows

1

Set up

#include <stdio.h> brings in printf / scanf. Set rows (fixed or from input).

Setup
2

Outer loop (rows)

for (i = 1; i <= rows; i++) selects the starting digit for each row.

Row
3

Inner loop (digits)

for (j = i; j <= rows; j++) prints digits i..rows with printf("%d", j).

Digits
4

New line

printf("\n") ends the row so the next outer iteration starts fresh.

Break
=

Left-shifted triangle complete

Total digit prints: 1+2+…+n = n(n+1)/2O(n²) time, O(1) extra memory.

🔎 Worked Walkthrough — rows = 4

Trace each outer-loop value of i (counting up) and the inner j range on each row.

iInner j rangePrinted rowDigits this row
11..412344
22..42343
33..4342
44..441

Total digit prints: 4 + 3 + 2 + 1 = 10 = 4×5/2.

Use Cases

Where this tiny pattern (and its loop structure) shows up beyond the homework prompt.

1. Teaching Nested Loops

Clearest visual proof that outer and inner bounds interact.

Example: change j <= rows and watch the shape change.

2. Pattern Series Base

Foundation for inverted, pyramid, diamond, and hollow variants.

Example: change inner start from j = i to j = 1 and compare with Program 1.

3. Console Formatting Drills

Practice printf vs row newline without complex math.

Example: put printf("\n") inside the inner loop by mistake.

4. Character Substitution

Swap digits for letters, stars, or spaced output once the loop works.

Example: print j + " " for spaced digits on each row.

5. Complexity Intuition

Triangular totals make O(n²) concrete for beginners.

Example: count printed digits for n = 10 → 55.

6. Input Validation Labs

Pair the pattern with scanf return checks and positive-row checks.

Example: reject rows <= 0 and re-prompt.

Pro Tip: when an interviewer asks for patterns, explain the outer/inner roles first — then write the loops. The story matters as much as the code.

Advantages

Why this pattern earns a permanent spot in beginner C courses.

  1. 1. Instant Visual Feedback

    Wrong bounds show up immediately as a broken staircase.

  2. 2. Minimal Concepts

    Only loops and console output — no arrays or math libraries.

  3. 3. Easy to Extend

    Invert, center, hollow, or change the fill character with small edits.

  4. 4. O(1) Extra Memory

    Streaming output needs no storage beyond loop counters.

Pro Tip: learn the nested-loop version first; treat putchar('0' + j) loop as a polish shortcut afterward.

Usage Tips

Small habits that keep number-pattern code clean.

  1. 1. Name Bounds Clearly

    Use rows (or n) and keep i/j for row/column — or rename to row/col.

  2. 2. Prefer scanf

    Check the return value so bad input does not leave rows uninitialized.

  3. 3. Keep printf("\n") Outside

    Only call printf("\n") after the inner loop finishes the row.

  4. 4. Start Inner Loop at i

    for (j = i; j <= rows; j++) matches “row i prints digits i..rows” naturally.

  5. 5. Dry-Run One Small n

    Trace rows = 3 on paper before coding larger demos.

Pro Tip: if the output is a vertical list of single digits, you almost certainly put printf("\n") inside the inner loop.

Common Pitfalls

Mistakes that commonly break left-shifted number patterns.

  1. 1. Newline Inside the Inner Loop

    Each digit lands on its own line — you get a column, not a triangle.

    → Use printf("%d", j) for digits; printf("\n") only after the inner loop.

  2. 2. Wrong Inner Start

    j = 1 prints Program 1’s shape; j <= i prints a growing triangle.

    → For this shape, keep for (j = i; j <= rows; j++).

  3. 3. Forgetting the Row Break

    Omitting printf("\n") glues every digit onto one endless line.

    → Always end the row after the inner loop.

  4. 4. Unchecked scanf

    Letters or empty input leave rows uninitialized.

    → Check scanf return value and re-prompt on failure.

  5. 5. Off-by-One on 0-Based Loops

    Switching to i = 0 without adjusting the inner bound prints an empty first row or wrong counts.

    → If 0-based, start inner at j = i and end at rows - 1 or adjust bounds.

Edge Cases

Check these inputs before calling the solution done.

rows = 1

Single digit row

Output is just 1 on one line.

rows = 0

Empty pattern

Outer loop never runs — print nothing or show a message.

Negative

rows < 0

Treat as invalid; re-prompt instead of silent empty output.

Large n

Many rows

Output grows as n²/2 characters — fine for labs, noisy for huge n.

Bad input

Non-numeric scanf input

Unchecked scanf leaves rows unset — check the return value.

Fill char

Spaced digits

Try printf("%d ", j) for spaces between numbers.

🎯 Practice Problems

Try these variations to lock in the pattern.

1. Classic descending triangle

  • Outer loop counts down; inner prints 1..i
  • Review Program 1

2. Reverse descending triangle

  • Continue with Program 3
  • Another inner-start variation

3. Safe input loop

  • Check scanf return value until rows >= 1
  • Then draw the triangle

4. Spaced output

  • Use printf("%d ", j) between digits
  • Harder follow-up after this page

Notes

  • Triangular count. Total digit prints for n rows is n(n+1)/2 — hence O(n²) time.
  • printf("%d", j) stays on the line; printf("\n") advances — mix them carefully.
  • Validate rows > 0 for interactive programs; rows = 1 should print a single 1.
  • This page is left-aligned. Centered pyramids need leading spaces — covered later in the series.

Quick Takeaway: outer loop picks start i, inner loop prints digits i..rows, then break the line — that is the whole pattern.

⏱️ Time and Space Complexity

ProgramTimeExtra space
Nested loops (Examples 1–2)O(rows²)O(1)
putchar('0' + j) loop (Example 3)O(rows²)O(rows) per row string (temporary)
Wrap Up

🎉 Conclusion

The left-shifted descending number triangle is a small nested-loop exercise with lasting payoff: changing the inner start value, printf vs row newline, and O(n²) intuition. Master the classic two-loop version, then optionally shorten rows with putchar('0' + j) loop.

Practice the three examples above, then continue to Program 3 for the reverse descending number triangle.

Row i prints i..rows — keep printf("%d", j) for digits and printf("\n") for the break, and validate row counts when reading input.

💡 Best Practices

✅ Do

  • Explain j = i inner start before coding
  • Use printf("%d", j) for digits and printf("\n") after each row
  • Validate rows ≥ 1 for interactive programs
  • Check scanf return value before using rows
  • State O(n²) time when asked about complexity

❌ Don’t

  • Call printf("\n") inside the inner digit loop
  • Use j = 1 when you meant left-shifted shape
  • Skip the newline after each row
  • Ignore bad console input in user-facing demos
  • Skip the rows = 1 edge case

Key Takeaways

Knowledge Unlocked

Five things to remember about this number pattern

Print the triangle the beginner-friendly way.

5
Core concepts
02

Outer loop

Controls each row

Code
1 03

Inner start

j = i, not j = 1

Code
04

Newline

Ends each row

I/O
O 05

Complexity

O(n²) time

Analysis

❓ Frequently Asked Questions

The inner loop starts at j = i, not j = 1. When i increases (1, 2, 3, ...), each row begins at that value and prints until rows.
Because each next row starts at a higher i, numbers below i are not printed anymore — the triangle shifts left visually.
printf("%d", j) stays on the same line. printf("\n") ends the current line. Digits use printf; the row break uses printf("\n") after the inner loop.
Program 1 counts the outer loop down and prints 1..i. Program 2 counts up and prints i..rows — same total prints, different shape.
Change the rows variable or read it with scanf. The outer loop runs from 1 to rows, and the inner loop prints j from i to rows.
Yes. putchar('0' + j) writes one digit when j is 1..9. Nested loops are still the best way to learn the bounds.
O(n²) for n rows because total prints are n+(n-1)+...+1 = n(n+1)/2.
Check scanf's return value: if (scanf("%d", &rows) != 1) handle bad input. Unchecked scanf leaves rows uninitialized on failure.
The outer loop never runs, so nothing is printed. Validate and prompt again if you want a clear user message.

Did you Know? 🔊

Each row starts at i and prints through rows, so the left edge shifts right each line — still O(n²) total prints for n rows.

Continue to Program 3

Move on to the reverse descending number triangle in the C number-pattern series.

Program 3 tutorial →

About the author

Mari Selvan M P
Mari Selvan M P 🔗

Developer, cloud engineer, and technical writer

  • Experience 12 years building web and cloud systems
  • Focus Full Stack Development, AWS, and Developer Education

I write practical tutorials so students and working developers can learn by doing—from databases and APIs to deployment on AWS.

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