In C, hypot() returns the length of the hypotenuse for the sides x and y. That is √(x² + y²). hypot(3, 4) is 5.
You pass two double values, and both are required. The result is a non-negative double. Include <math.h>.
Pass the two sides. Start with this call.
hypot(3.0, 4.0);| Call | What it does |
|---|---|
hypot(3.0, 4.0) | Returns 5, the distance for sides 3 and 4. |
Include <math.h>. On GCC, link with -lm.
double hypot(double x, double y);
float hypotf(float x, float y);
long double hypotl(long double x, long double y);| Parameter | Description |
|---|---|
| x | Required. One side of the right triangle. |
| y | Required. The other side. |
| Return Value | Description |
|---|---|
| Distance | A non-negative double, √(x² + y²). |
Compute the long side of a right triangle with legs 3 and 4.
#include <stdio.h>
#include <math.h>
int main(void) {
printf("%.1f\n", hypot(3.0, 4.0));
printf("%.1f\n", hypot(-3.0, 4.0));
return 0;
}hypot.%.1f shows one decimal place.Pass the differences in x and y to get Euclidean distance in the plane.
#include <stdio.h>
#include <math.h>
int main(void) {
double x1 = 1.0, y1 = 2.0;
double x2 = 4.0, y2 = 6.0;
double d = hypot(x2 - x1, y2 - y1);
printf("distance = %.1f\n", d);
return 0;
}4-1 = 3 and 6-2 = 4.hypot(3, 4) → 5.hypot Over Naive sqrtFor huge legs, x*x can overflow even when the true hypotenuse still fits in a double.
#include <stdio.h>
#include <math.h>
int main(void) {
double x = 1e200;
double y = 1e200;
printf("hypot = %g\n", hypot(x, y));
/* sqrt(x*x + y*y) may become inf here */
return 0;
}1e200.(1e200)² directly as an overflowing square.√2 × 1e200.hypot whenever overflow of intermediate squares matters.Scale a mantissa by multiplying with 2 raised to an exponent.
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