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C Alphabet Pattern 33

Posted in C Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 142 - Views
⏳ 4 mins
💬 1 Comment
C Alphabet Pattern 33

Photo Credit to CodeToFun

C Alphabet Pattern 33

Here`s a program that prints the above alphabet pattern using C Programming:

example.c
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#include <stdio.h>

int main() {
  int i, j, k;
  for (i = 65; i <= 69; i++) {
    for (j = 69; j >= 65; j--) {
      if (i == j)
        printf("%c", j);
      else
        printf(" ");
    }
    for (k = 66; k <= 69; k++) {
      if (i == k)
        printf("%c", k);
      else
        printf(" ");
    }
    printf("\n");
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
     A
    B B
   C   C
  D     D
 E       E

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program starts with the inclusion of the standard input/output library stdio.h.
  2. The main() function is defined, which is the entry point of the program.
  3. Three integer variables i, j, and k are declared.
  4. The outer for loop starts with i initialized to 65 (ASCII value of 'A') and continues until i is less than or equal to 69 (ASCII value of 'E').
  5. Inside the outer loop, there is an inner for loop with j initialized to 69 (ASCII value of 'E') and continues until j is greater than or equal to 65 (ASCII value of 'A').
  6. Within the inner loop, there is an if statement that checks if i is equal to j.
  7. If i is equal to j, it means that the current iteration of the outer loop matches the current iteration of the inner loop. In this case, the program prints the character represented by the ASCII value of j using the %c format specifier and the printf() function.
  8. If i is not equal to j, the else part of the if statement is executed. It prints a space character using the printf() function.
  9. After the inner loop, there is another inner for loop with k initialized to 66 (ASCII value of 'B') and continues until k is less than or equal to 69 (ASCII value of 'E').
  10. Inside this loop, there is another if statement that checks if i is equal to k.
  11. If i is equal to k, it means that the current iteration of the outer loop matches the current iteration of this second inner loop. In this case, the program prints the character represented by the ASCII value of k using the %c format specifier and the printf() function.
  12. If i is not equal to k, the else part of the if statement is executed. It prints a space character using the printf() function.
  13. After the second inner loop, the program prints a newline character (\n) using the printf() function. This moves the cursor to the next line.
  14. The outer loop continues to the next iteration, and steps 5-13 are repeated until i becomes greater than 69 (ASCII value of 'E').
  15. Finally, the main() function returns 0, indicating successful execution of the program.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
9 months ago

If you have any doubts regarding this article (C Alphabet Pattern 33) please comment here. I will help you immediately.

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