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C Alphabet Pattern 28

Posted in C Tutorial
Updated on Jan 10, 2024
By Mari Selvan
👁️ 135 - Views
⏳ 4 mins
💬 1 Comment
C Alphabet Pattern 28

Photo Credit to CodeToFun

C Alphabet Pattern 28

Here`s a program that prints the above alphabet pattern using C Programming:

example.c
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#include <stdio.h>

int main() {
  int i, j;
  int k = 69;
  for (i = k; i >= 65; i--) {
    for (j = k; j >= 65; j--) {
      if (j > i)
        printf("%c ", j);
      else
        printf("%c ", i);
    }
    for (j = 66; j <= k; j++) {
      if (j > i)
        printf("%c ", j);
      else
        printf("%c ", i);
    }
    printf("\n");
  }
  return 0;
}

💻 Testing the Program

When you run the above program, it will print the following output:

Output
E E E E E E E E E
E D D D D D D D E
E D C C C C C D E
E D C B B B C D E
E D C B A B C D E

🧠 How the Program Works

Let's break down the logic behind the code:

  1. The program starts by including the necessary header file stdio.h, which contains the standard input/output functions.
  2. The main() function is declared as an int type, indicating that it will return an integer value to the operating system when it finishes executing.
  3. Two integer variables i and j are declared without any initial values.
  4. Another integer variable k is declared and initialized with the value 69.
  5. The program enters a for loop with the variable i starting at the value of k (69) and iterates as long as i is greater than or equal to 65. This loop is responsible for printing the pattern.
  6. Inside the outer loop, there is another for loop with the variable j also starting at the value of k (69) and iterating as long as j is greater than or equal to 65. This loop controls the columns of each row in the pattern.
  7. Within the nested loop, there is an if statement that compares j with i. If j is greater than i, it prints the character represented by the ASCII value of j. Otherwise, it prints the character represented by the ASCII value of i. This determines the characters to be printed in each column.
  8. After the nested loop, there is another for loop that starts with j initialized to 66 and continues as long as j is less than or equal to k (69). This loop is responsible for printing the second half of each row, which includes characters greater than i.
  9. Inside this second nested loop, there is a similar if statement that determines whether to print j or i based on the comparison.
  10. After the completion of the inner nested loop, the program prints a newline character to move to the next row in the pattern.
  11. The outer loop continues to iterate until i becomes less than 65, and then the program exits the loop.
  12. Finally, the main() function returns 0 to indicate successful execution to the operating system, and the program terminates.

💯 Tips for Enhancement:

Explore the versatility of this pattern by adjusting its parameters. Whether you increase or decrease the size, tweak the spacing, or modify the characters used, each change opens up a world of possibilities, allowing you to customize and create your unique visual effects.

✔ Conclusion:

Creating visually appealing patterns is not only a fun endeavour but also a great way to enhance your programming or design skills. We hope this tutorial has inspired you to explore the world of creative coding. Share your creations with us, and let your imagination run wild!

🤗 Closing Call-to-Action:

We'd love to see your unique interpretations of the alphabet pattern. Share your creations in the comments below, and don't hesitate to reach out if you have any questions or suggestions for future tutorials. Happy coding!

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Author

author
👋 Hey, I'm Mari Selvan

For over eight years, I worked as a full-stack web developer. Now, I have chosen my profession as a full-time blogger at codetofun.com.

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Mari Selvan
Mari Selvan
11 months ago

If you have any doubts regarding this article (C Alphabet Pattern 28) please comment here. I will help you immediately.

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